To find the rate, you must divide the distance traveled by the time it took.
17.5 m is the distance while time it took was 5 seconds.
So,
17.5 ÷ 5 = 3.5 m/s
The rate of the anchor is 3.5 m/s
Note: I did not ignore the negative sign in the distance but rather acknowledged it as a magnitude. This meant that the anchor was dropping down instead of going up.
Answer:
875
Step-by-step explanation:
lets assume the original amount X
the new amount = X - ( X × 40% )
525 = (60 × X) ÷ 100
X = ( 525 × 100 ) ÷ 60
<u>X = 875</u>
In the first column the decimal is .26 and the percent is 26%. In the second column the fraction is 31/50 and the percent is 62%. In the last column the fraction is 9/20 and the decimal is .45. Hope this helps! ;)
Answer:
83
Step-by-step explanation:
The total angle of a flat line is 180. If you subtract the angle of 2 from 180 you get 83 which is the angle of 1.
The surface area of a sphere is given by
![S = 4\pi r^2](https://tex.z-dn.net/?f=S%20%3D%204%5Cpi%20r%5E2)
We deduce
![r = \sqrt{\dfrac{S}{4\pi}}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%7B%5Cdfrac%7BS%7D%7B4%5Cpi%7D%7D)
So, in your case, the radius is
![r = \sqrt{\dfrac{100\pi}{4\pi}}=\sqrt{25}=5](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%7B%5Cdfrac%7B100%5Cpi%7D%7B4%5Cpi%7D%7D%3D%5Csqrt%7B25%7D%3D5)
The volume of a sphere is given by
![V=\dfrac{4}{3}\pi r^3](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3)
So, we have
![V = \dfrac{4}{3} \pi 5^3 = \dfrac{500}{3}\pi](https://tex.z-dn.net/?f=V%20%3D%20%5Cdfrac%7B4%7D%7B3%7D%20%5Cpi%205%5E3%20%3D%20%5Cdfrac%7B500%7D%7B3%7D%5Cpi)