You divide 24 by 3 and get 8 then subtract 2
Well, if 150 grams is used for 5 cakes, we can divide that.
150/5=30. 30 grams of sugar are used for each cake
You want to know how many grams for 7 cakes
30x7=<u><em>210 grams of sugar are used for seven cakes.
</em></u>Hope this helps!<u><em>
</em></u>
To solve for this, we need to figure out the sum of any two numbers on the dice that will become a pair factor for the listed answers.
What I mean by that is that we need to find the probability between how many two numbers will sum up to the answer.
3 can be 1 + 2, that's it. 3 has a probability of (1).
4 has a sum of 1 + 3, and 2 + 2, that's it. 4 has a probability of (2).
7 has a sum of 1 + 6, 2 + 5, and 3 + 4. 7 has a probability of (3).
11 has a sum of 5 + 6, that's it. 11 has a probability of (1).
The numbers in parenthesis are the probabilities.
7 has the highest number, so 7 has the highest probability.
Your answer is: 7.
I hope this helps!
Multiply the coefficients and the powers of 10 with each other:
![(3.8 \times 10^{-6}) \times (2.37 \times 10^{-3}) = (3.8\times2.37) \times (10^{-6} \times10^{-3})](https://tex.z-dn.net/?f=%283.8%20%5Ctimes%2010%5E%7B-6%7D%29%20%5Ctimes%20%282.37%20%5Ctimes%2010%5E%7B-3%7D%29%20%3D%20%283.8%5Ctimes2.37%29%20%5Ctimes%20%2810%5E%7B-6%7D%20%5Ctimes10%5E%7B-3%7D%29)
The numeric part simply yields
![3.8\times2.37 = 9.006](https://tex.z-dn.net/?f=%203.8%5Ctimes2.37%20%3D%209.006%20)
As for the powers of 10, you have to add the exponents, using the rule
![a^b \times a^c = a^{b+c}](https://tex.z-dn.net/?f=%20a%5Eb%20%5Ctimes%20a%5Ec%20%3D%20a%5E%7Bb%2Bc%7D%20)
So, we have
![10^{-6} \times10^{-3} = 10^{-6-3} = 10^{-9}](https://tex.z-dn.net/?f=%2010%5E%7B-6%7D%20%5Ctimes10%5E%7B-3%7D%20%3D%2010%5E%7B-6-3%7D%20%3D%2010%5E%7B-9%7D)
So, the final answer is
![9.006\times 10^{-9}](https://tex.z-dn.net/?f=%209.006%5Ctimes%2010%5E%7B-9%7D%20)
The origin is (0,0)
y = mx + b
slope(m) = 2/3
(0,0)...x = 0 and y = 0
now we sub and find b, the y int
0 = 2/3(0) + b
0 = b
so ur equation is y = 2/3x + 0...or just y = 2/3x