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3 years ago

I need help super bad!!!!

Mathematics

1 answer:

Marysya12 [62]3 years ago

3 0

4x+7y=47 /*4 ------>16x + 28y=188
5x-4y=-5 /*7 -------->35x-28y=-35

16x + 28y=188, add this two equations
35x-28y=-35

16x + 28y+35x-28y=188-35
16x +35x=188-35
51x =153m
x=3

5x-4y=-5
5*3-4y=-5
15-4y=-5
4y=15+5
4y=20
y=5

Answer (3,5), B

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Answer:

The proportions of the females and males who took the survey who are annoyed by the behavior in question are 0.3301 and_0.3791 respectively

D) The data come from a Population that is Normally distributed

F) the samples are independent

c)

Null hypothesis: H₀: $p_{m} ^{-} - p^{-} _{fm} \leq 0$

Alternative Hypothesis H₁: $p_{m} ^{-} - p^{-} _{fm} \geq 0$

Step-by-step explanation:

Given data Among the 530 males surveyed, 175 responded "Yes

The sample proportion of males

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The sample proportion of 575 Females surveyed, 218 responded "Yes

$p_{fem} ^{-} = \frac{x}{n} = \frac{218}{575} = 0.3791$

The proportions of the females and males who took the survey who are annoyed by the behavior in question are 0.3301 and_0.3791 respectively

The data come from a Population that is normally distributed.

The two samples are independent

Null hypothesis: H₀: $p_{m} ^{-} - p^{-} _{fm} \geq 0$

Alternative Hypothesis H₁: $p_{m} ^{-} - p^{-} _{fm} \leq 0$

We will use two samples Z - hypothesis test

$Z = \frac{p^{-} _{m} - p^{-} _{fem} }{se(p^{-} _{m}-p^{-} _{fem} ) }$

$Se(p_{m} -p_{fem}) = \sqrt{\frac{p_{m}(1-p_{m}) }{n_{m} }+\frac{p_{fem} (1-p_{fem} )}{n_{fem} } }$

$Se(p_{m} -p_{fem}) = \sqrt{\frac{0.3301(1-0.3301) }{530 }+\frac{0.3791(1-0.3791)}{575} }$

$Se(p_{m} ^{-} - p^{-} _{fem} ) = \sqrt{0.000826} = 0.0287$

The test statistic

$Z = \frac{0.3301-0.3791}{0.02875}$

Z = -1.7043

|Z| = |-1.7043|

The tabulated value Z₀.₉₅ = 1.96

The calculated Z= 1.7043 < 1.96 at 0.05 level of significance

The null hypothesis is accepted

Conclusion:-

The evidence suggest not a higher proportion of females are annoyed by this behavior

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3 years ago

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