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Sav [38]
3 years ago
5

Oranges cost 25 cents for 1/2 kilograms. How much would 8 kilograms of oranges cost?

Mathematics
2 answers:
eimsori [14]3 years ago
6 0
\dfrac{1}{2} \text{ kg} \longrightarrow 25 \text{ cents}

Find 1 kg:
1 \text{ kg} \longrightarrow 25 \times 2 \text{ cents}

1 \text{ kg} \longrightarrow 50 \text{ cents}

Find 8 kg:
8\text{ kg} \longrightarrow 50 \times 8 \text{ cents}

8\text{ kg} \longrightarrow 400 \text{ cents or } \$4.00

Answer: 8 kg of oranges cost $4.00

lakkis [162]3 years ago
5 0
The cost of 8 kilograms of oranges cost 4$
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Answer:

The dimension of the plot is 30 yd by 20 yd

Step-by-step explanation:

Given;

Area = 600 yd^2

Length = width + 10

l = w + 10 ......1

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Area A = length × width

A = l × w

Substituting equation 1;

A = (w+10) × w

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w^2 +10w -600 = 0

Solving the quadratic equation;

w = -30 or 20

cannot be negative

w = 20 yd

l = w+10 = 20+10 = 30yd

The dimension of the plot is 30 yd by 20 yd

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3 years ago
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DIA [1.3K]
2/6 = 1/3 = 20 minutes
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Add $26.25 to the total for 50 minutes to get your answer. :)
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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