Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
The function best models the linear relationship is y=12,000x+40,000.
Wen you deduct an amount from something
Answer:
66ft^2
Step-by-step explanation:
Note the hundredth place value (underlined and bolded):
9.3<u>7</u>5
Look at the number to the right of the hundredth place value. It is a 5. Because you round up if the number is 5 or greater, you round up in this case (you round down if it is 4 or less).
9.375 rounded to the nearest hundredth is 9.38
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