<span>
Solving:
1)
-58 - 6x = 42 + 4x
</span>Pass the numbers with letter to the left and the numbers without letter to the right, changing the signal as they change sides.
<span>- 6x - 4x = 42 + 58
- 10x = 100 simplify by (-1)
10x = - 100
</span>


<span>
2)
37 + 5x = -2x - 33
</span>Pass the numbers with letter to the left and the numbers without letter to the right, changing the signal as they change sides.
<span>5x + 2x = - 33 - 37
7x = - 70
</span>


<span>
3)
27 - 9x = -6x - 39
</span>Pass the numbers with letter to the left and the numbers without letter to the right, changing the signal as they change sides.
- 9x + 6x = - 39 - 27
- 3x = - 66 simplify by (-1)
3x = 66

ANSWER
(C)38.16
EXPLANATION
The acute angle given in the right triangle is 27°.
The side length adjacent to the 27° angle is 34 units.
The side length we want to find is x units, which is the hypotenuse of the right triangle.
We use the cosine ratio to obtain:


Solve for x,


to the nearest hundredth.
Multiply both sides by <span>cos</span><span>
</span><span>r<span>cos<span>(θ)</span></span>=<span>sec<span>(θ)</span></span><span>cos<span>(θ)</span></span>=1</span><span>
</span><span>x=r<span>cos<span>(θ)</span></span></span><span>
</span><span>x=1</span>
A) Total points = 3W + 2T + 1L
b) (3*5) + (2*2) + (3*1)
15 + 4 + 3 = 22
The Black Scot’s total points were 22
c) so, Wins + Ties + Losses = 10 because there were only 10 games played. but we also have to remember that we only can have 22 points. I just randomly plug in numbers until I get what I am looking for.
so I did 4 wins, 4 ties, and 2 losses. this is a total of 10 games, and the points equal 22. we just plug those values into our first equation:
(3*4) + (2*4) + (1*2)
12 + 8 + 2 = 22 points