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2 years ago

What is the answer to Which expression is equivalent to 6(3m+9).

Mathematics

1 answer:

GenaCL600 [577]2 years ago

7 0

Answer:

Step-by-step explanation:

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A baker knows that the daily demand for strawberry pies is a random variable that follows the normal distribution with a mean of

Elan Coil [88]

The demand that has an 8% probability of being exceeded is 38.1230 .

<h3>What is probability?</h3>

Probability is the aspect of mathematics that focus on the occurrence of a random event.

This is calculated below:

The normal random variable having the mean is been given as :

(Mu = 31.8)

The standard deviation is been given as ( sd = 4.5)

Then in making our calculation, we will need to make use of the formular below:

$\\Z= (X - Mu) / sd = (X - 31.8) / 4.5$

But we know that going with the probability of 0.08

where k = 1.4051

P (Z > 1.4051)

k = 1.4051

we can have the expression for k as $[(X - 31.8) / 4.5]$

This can be simplified as:

X = 4.5 (1.4051) + 31.8 = 38.1230.

Therefore, the demand that has an 8% probability of being exceeded is 38.1230 .

Learn more about normal distribution on:

brainly.com/question/4079902

#SPJ1

5 0

2 years ago

(3x^2 + 8x - 4 ) -(-x^2 +5x +2) simplify

xxMikexx [17]

Answer:

4x^2+3x-6

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Do these ratios form a proportion? 26 medium hats to 2 small hats 39 medium hats to 3 small hats

inessss [21]

$\bf \cfrac{\textit{medium hats}}{\textit{small hats}}\qquad \qquad \cfrac{26}{2}=\cfrac{39}{13}\implies \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 13}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=\cfrac{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 13}{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies 13= 13~~\textit{\Large \checkmark}$

7 0

3 years ago

Read 2 more answers

Find the Fourier series of f on the given interval. f(x) = 1, ?7 < x < 0 1 + x, 0 ? x < 7

Zolol [24]

$f(x)=\begin{cases}1&\text{for }-7$

The Fourier series expansion of $f(x)$ is given by

$\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7$

where we have

$a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx$
$a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)$
$a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2$

The coefficients of the cosine series are

$a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx$
$a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)$
$a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}$
$a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}$

When $n$ is even, the numerator vanishes, so we consider odd $n$ , i.e. $n=2k-1$ for $k\in\mathbb N$ , leaving us with

$a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}$

Meanwhile, the coefficients of the sine series are given by

$b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx$
$b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)$
$b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}$
$b_n=\dfrac{7(-1)^{n+1}}{n\pi}$

So the Fourier series expansion for $f(x)$ is

$f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7$