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lawyer [7]
3 years ago
12

Simplify (4x-6)-(3x+6)

Mathematics
1 answer:
DaniilM [7]3 years ago
3 0

Answer:

x-12

Step-by-step explanation:

First open the brackets

=(4x-6)-(3x+6)\\\\\\=4x-6-3x-6

Then collect the like terms

4x-3x-6-6

Solve the like terms

4x-3x=x\\\\\\-6-6=-12\\\\\\=x-12

The simplified form is

x-12

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Answer:

The slope of AB is -7/4, the slope of BC is 1/7 , the slope of CD is 5/3, and the slope of AD is 2. So, Quadrilateral ABCD is neither a parallelogram nor a trapezoid because neither pair of opposite sides are parallel.

Step-by-step explanation:

Since, a quadrilateral having,

One pair of parallel opposite sides is Trapezoid,

While, having two pair of parallel opposite sides is parallelogram.

Since, the slope of a line segment having the end points (x_1, y_1) and (x_2, y_2) is,

m=\frac{y_2-y_1}{x_2-x_1}

Here, the vertices of the quadrilateral ABCD are A(0, −4) , B(−4, 3) , C(3, 4) , and D(6, −1),

Slope of AB = \frac{3+4}{-4-0}=-\frac{7}{4}

Slope of BC = \frac{4-3}{3+4}=\frac{1}{7}

Slope of CD = \frac{-1-4}{6-3}=-\frac{5}{3}

Slope of AD = \frac{-1+4}{6-0}=\frac{3}{6}=2

Hence, Quadrilateral ABCD is neither a parallelogram nor a trapezoid because neither pair of opposite sides are parallel.

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A. In a composition of two functions the first function is evaluated, and then the second function is evaluated on the result of the first function. In other word, you are going to evaluate the second function in the first function.

Remember that you can evaluate function at any number just replacing the variable in the function with the number. For example, let's evaluate our function f(x) at x=1:

f(x)=\frac{1}{x-3}

f(1)=\frac{1}{1-3}

f(1)=\frac{1}{-2}

Similarly, to find the composition of f(x) andg(x), we are going to evaluate f(x) at g(x). In other words, we are going to replace x in f(x) with \frac{3x+1}{x}:

f(x)=\frac{1}{x-3}

f(g(x) = f(\frac{3x+1}{x} ) = \frac{1}{\frac{3x+1}{x} -3}

Remember that two functions are inverse if after simplifying their composition, we end up with just x. Let's simplify and see what happens.

f(g(x)=\frac{1}{\frac{3x+1}{x} -3}

f(g(x)=\frac{1}{\frac{3x+1-3x}{x} }

f(g(x)=\frac{1}{\frac{1}{x} }

f(g(x)=x

Now let's do the same for g(f(x)):

g(\frac{1}{x-3} )=\frac{3(\frac{1}{x-3})+1}{x}

g(\frac{1}{x-3} )=\frac{\frac{3}{x-3}+1}{x}

g(\frac{1}{x-3} )=\frac{\frac{3+x-3}{x-3}}{x}

g(\frac{1}{x-3} )=\frac{\frac{x}{x-3}}{x}

g(\frac{1}{x-3} )=\frac{x}{x(x-3)}

g(f(x))=\frac{x}{x(x-3)}

We can conclude that g(x) is the inverse function of f(x), but f(x) is not the inverse function of g(x).

B. The domain of a function is the set of all the possible values the independent variable can have. In other words, the domain are all the possible x-values of function.

Now, interval notation is a way to represent and interval using an ordered pair of numbers called the end points; we use brackets [ ] to indicate that the end points are included in the interval and parenthesis ( ) to indicate that they are excluded.

Notice that when x=0, g(x)=\frac{3(0)+1}{0} =\frac{0}{0}, so when x=0, g(x) is not defined; therefore we have to exclude zero from the domain of f(g(x)).

We can conclude that the domain of the composite function f(g(x)) in interval notation is (-∞,0)U(0,∞)

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Notice that the composition is not defined when its denominator equals zero, so we are going to set its denominator equal to zero to find the values we should exclude from its domain:

x(x-3)=0

x=0 and x-3=0

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Know we know that we need to exclude x=0 and x=3 from the domain of g(f(x)).

We can conclude that the domain of the composition function g(f(x)) is (-∞,0)U(0,3)U(3,∞)

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