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vichka [17]
3 years ago
15

A rectangle has length 12 feet and width 8 feet. Every dimension of the rectangle is multiplied by 3/4 to form a similar rectang

le. How is the ratio of the areas related to the ratio of corresponding side
Mathematics
1 answer:
kap26 [50]3 years ago
8 0
Let the area of the original rectangle be A₁.

A₁ = (12 ft)(8 feet) = 96 ft²

To determine the area of the reduced triangle, let's compute the new dimensions first.

Length = 12 ft * 3/4 - 9 ft
Width = 8 ft *3/4 = 6 ft

Thus, the area of the new rectangle denoted as A₂ is
A₂ = (9 ft)(6 ft) = 54 ft

The ratio of the areas are:
A₂/A₁ = 54/96 = 9/16
The ratio of the sides are given to be 3/4.
Finally the ratios of the area to side would be:
Ratio = 9/16 ÷ 3/4 = 3/4

Therefore, the ratio of the areas is 3/4 of the ratio of the corresponding sides.
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We take the value of F in the inequality by taking the inequalities in group. Let the first group be:

(1)    -20 ≤ 59(F - 32)

Then, the second group would be,
(2)     59(F - 32) ≤ - 15

Calculating for the values of F,

(1)     -20 ≤ 59F - 1888
          1888 - 20 ≤ 59F
              1868 ≤ 59F
                 F ≥ 31.66

(2)     (59)(F - 32) ≤ - 15
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The values of F are therefore,
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