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JulijaS [17]
3 years ago
8

PLEASE HELP ASAP!! CORRECT ANSWERS ONLY PLEASE!!!

Mathematics
2 answers:
alexgriva [62]3 years ago
7 0

Answer:A

Step-by-step explanation:

melisa1 [442]3 years ago
3 0

Answer:49 %

Step-by-step explanation:

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Need help on this one please
Archy [21]
The answer is A because there are only acute angles
3 0
3 years ago
Solve the problem by multiplying first. A clothing store is having a sale on shirts and jeans. Four shirts and two pairs of jean
ella [17]

We will solve this by suing simultaneous equations,

⇒ 5s + 3j = 87

    4s + 2j = 64

Multiply the first equation with 4 and the second one with 5, this is to get one of the values equal so that we can cancel them out,

⇒ (5s + 3j = 87) × 4

    (4s + 2j = 64) × 5

∴ ⇒ 20s + 12j = 348

       20s + 10j = 320

Subtract both the equations. This is how your result (after subtraction) should look like,

  ⇒ 2j = 28

∴ ⇒ j = $14

Now replace the value of 'j' in one of the original equations,

⇒ 4s + 2(14) = 64

⇒ 4s + 28 = 64

⇒ 4s = 64 - 28

⇒ 4s = 36

∴ ⇒ s = $9

Therefore, one pair of jeans cost $14 and a shirt costs $9

Hope you understood! Feel free to ask me if you didn't understand a step.

5 0
2 years ago
F. one die is rolled 3 times. what is the chance of getting no 2's?
aniked [119]
6^3 = 216. When using chance, take the number of outcomes(six for a die) and raise it to the power of the number of repetitions 
6 0
2 years ago
Whats the lowest common multiple of 120 and 19600​
Levart [38]

Answer:

Multiples of 120 are 120, 240, 360, 480, 600, 720, 840 etc; Multiples of 150 are 150, 300, 450, 600, 750, 900 etc; Therefore, the least common multiple of 120 and 150 is 600.

Least common multiple (LCM) of 19600 and 19619 is 384532400.

4 0
2 years ago
Read 2 more answers
An appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W. From pre
melamori03 [73]

Answer:

We conclude that a compact microwave oven consumes a mean of more than 250 W.

Step-by-step explanation:

We are given that an appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W with a population standard deviation of 15 W.

They take a sample of 20 microwave ovens and find that they consume a mean of 257.3 W.

Let \mu = <u><em>mean power consumption for microwave ovens.</em></u>

So, Null Hypothesis, H_0 : \mu \leq 250 W     {means that a compact microwave oven consumes a mean of no more than 250 W}

Alternate Hypothesis, H_A : \mu > 250 W     {means that a compact microwave oven consumes a mean of more than 250 W}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                                T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean power consumption for ovens = 257.3 W

            σ = population standard deviation = 15 W

            n = sample of microwave ovens = 20

So, <em><u>the test statistics</u></em>  =  \frac{257.3-250}{\frac{15}{\sqrt{20} } }

                                      =  2.176

The value of z test statistics is 2.176.

<u>Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.</u>

Since our test statistic is more than the critical value of t as 2.176 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that a compact microwave oven consumes a mean of more than 250 W.

7 0
2 years ago
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