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sveta [45]
2 years ago
6

PLEASE HELP ME FAST I NEED THE SOLUTION REALLY QUICK

Mathematics
1 answer:
rosijanka [135]2 years ago
7 0

Answer:

WHERE IS THE QUESTION

Step-by-step explanation:

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Step-by-step explanation:

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\bf \qquad \textit{parabola vertex form}\\\\\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array}\qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex\ (-4,6)\qquad 
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h=-4\\
k=6
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\\\\\\
y=a(x+4)^2+6
\\\\\\
\textit{we also know that }
\begin{cases}
x=-3\\
y=14
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solve for "a"
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