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3 years ago

Write an equation of the line that has a slope of -5 and a y intercept of 4 in slope intercept form.

Mathematics

2 answers:

maks197457 [2]3 years ago

5 0

Y = mx+b
m = slope
b = y-intercept

Ans: y = -5x + 4

sp2606 [1]3 years ago

3 0

Y=-5x+4
Hope this helps:)

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2 years ago

Which point is 10 units from (2,5)

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Answer:

All the points on (x - 2)² + (y - 5)² = 100

Step-by-step explanation:

It should be the circle with its center on point (2,5) and radius is 10.

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3 years ago

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Sladkaya [172]

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$\large\boxed{\cot\theta(\tan\theta+\cot\theta)=1+\cot^2\theta=\dfrac{1}{\sin^2\theta}=\csc^2\theta}$

Step-by-step explanation:

$\text{Use}\\\\\text{distributive property:}\ a(b+c)=ab+ac\\\cot\alpha\tan\alpha=1.\\\\======================\\\\\cot\theta(\tan\theta+\cot\theta)=(\cot\theta)(\tan\theta)+(\cot\theta)(\cot\theta)\\\\=1+\cot^2\theta\\\\\text{If you want next transformation, then use:}\\\\\cot\alpha=\dfrac{\cos\alpha}{\sin\alpha}\\\\\sin^2\alpha+\cos^2\alpha=1\\\\=======================$

$=1+\left(\dfrac{\cos\theta}{\sin\theta}\right)^2=1+\dfrac{\cos^2\theta}{\sin^2\theta}=\dfrac{\sin^2\theta}{\sin^2\theta}+\dfrac{\cos^2\theta}{\sin^2\theta}=\dfrac{\sin^2\theta+\cos^2\theta}{\sin^2\theta}\\\\=\dfrac{1}{\sin^2\theta}\\\\\text{If you want next transformation, then use:}\\\\\csc\alpha=\dfrac{1}{\sin\alpha}\\\\=\left(\dfrac{1}{\sin\theta}\right)^2=(\csc\theta)^2=\csc^2\theta$

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