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3 years ago

Ive been stuck on this expression for a while now

Mathematics

1 answer:

natka813 [3]3 years ago

4 0

Answer:

xy^(2)z^(6)

Step-by-step explanation:

i hope that helps you :)

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1/2 x 2 1/2 as a fraction in simplest form plz help fast

Naily [24]

5/4. first, convert the mixed fraction into an improper fraction to get 5/2. multiply the 5/2 to the 1/2. multiplying the numerators gets you 5. the denominators being multiplied gets you 4. 5 is the new numerator, 4 is the new denominator. 5/4 is in simplest form

7 0

3 years ago

57 1/2 as a decimal, Please help and Thanks

Nimfa-mama [501]

The answer is 57.5 because 57 represents a whole number and 1/2 equals .5 so 57.5.

People who answer the question will get a thank you!

4 0

3 years ago

74ft <br> 24ft <br> b<br> What is the length of the missing leg?

amm1812

Answer: 70

Step-by-step explanation:

a^2 + b^2 = c^2

24^2 + b^2 = 74^2

576 + b^2 = 5,476

-576 -576

b^2 =4,900

(square root)

b =70

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2 years ago

How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?

BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

$\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}$

Where n = 8 and r = 0,1....8

When r = 0

$\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1$

When r = 1

$\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 2

$\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8$

When r = 3

$\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 4

$\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70$

When r = 5

$\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$