Answer:25
Step-by-step explanation:
If you add the 20+5
Answer:
Here you go :)
Step-by-step explanation:

Taking the square root of both sides gives two possible cases,

or

Recall that

If
and
, we have

so in the equations above, we can write

Then in the first case,


(where
is any integer)


and in the second,




Then the solutions that fall in the interval
are

Answer:
it's 47÷4=11 3/4 will be your final answer
Answer:
x = 3 (see below)
Step-by-step explanation:
To solve for x, you need to isolate the variable to one side of the equation. To do that, you need to use reverse operations. For example, the reverse operation of subtraction is addition.
In this case, we have:
15 = 5x
5x is the same thing as 5 (x) or 5 times x. This means the reverse operation is division. So, we need to divide both sides of the equation by 5:
15 = 5x
----- ----
5 5
--------------
3 = x
x = 3