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tiny-mole [99]
4 years ago
7

------------÷ 34 = 20 rem 12 How do you do this problem

Mathematics
1 answer:
Alborosie4 years ago
8 0
Hello,

Let's the unkown dividende:

x=20*34+12

==>x=692

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What is the value of x<br><br> Triangle with sides 10 6 x-6
Grace [21]
Given that the triangle is a right angled triangle, to solve for x we shall use the Pythagorean theorem given by:
c^2=a^2+b^2
where:
c is the hypotenuse
a and b are the legs.
c=10
a=6
b=(x-6)
thus plugging the values in the equation and solving for x we get:
10^2=6^2+(x-6)^2
100=36+x^2-12x+36
100=x^2-12x+72
0=x^2-12x-28
factoring the above we get:
0=(x+2)(x-14)
hence
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5 0
4 years ago
1) Bob weighed 200 lbs, but after dieting for 6 months, he weighed 170 lbs.
aivan3 [116]

Answer: 15%

Step-by-step explanation:

The Percentage decrease will be:

= Decrease in weight / Old weight × 100

= (200 - 170) / 200 × 100

= 30/200 × 100

= 15%

The Percentage decrease is 15%

7 0
3 years ago
Solve the equation, and check your solution.<br> -3/5n = -9
jasenka [17]

Answer:

-15 = n

Step-by-step explanation:

5 0
3 years ago
If the population of a country increases at a rate of 1.5% annually, and its current population is 430,000, how many years will
Alchen [17]
For this case we have an equation of the form:
 y = A * (b) ^ t&#10;
 Where,
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 b: growth rate
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 y = 430000 * (1,015) ^ t&#10;
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 3 * 430000 = 430000 * (1,015) ^ t&#10;
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 3 = (1,015) ^ t&#10;
 Clearing t we have:
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It will take for the population to triple about:
 
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3 0
4 years ago
A sample was taken of the salaries of 20 employees from a large company. The following are the salaries (in thousands of dollars
seropon [69]

Answer:

21,500

Step-by-step explanation:

Given data ( in thousand ) in this year,

28 31 34 35 37 41 42 42 42 47 49 51 52 52 60 61 67 72 75 77,

If each data is increased by $ 3000 in the next year,

So, the data for the next year,

31 34 37 38 40 44 45 45 45 50 52 54 55 55 63 64 70 75 78 80,

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The median is 51 which is between 50 and 52,

Thus, the lower half of the Data is, 31 34 37 38 40 44 45 45 45 50,

Having median Q_1=\frac{40+44}{2} = \frac{84}{2} = 42,

Upper half of the data is 52 54 55 55 63 64 70 75 78 80,

Having median Q_3=\frac{63+64}{2}=\frac{127}{2} = 63.5

Hence, the interquartile range = Q_3-Q_1

= 63.5 - 42

= 21.5

That is, the Interquartile range would be 21, 500.

7 0
4 years ago
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