-16 p + 37 = 49

Jessica is buying several bunches of bananas to make desserts for a fundraiser. She can buy 10 pounds of bananas at Smiths for $

ZanzabumX [31]

Answer:

$1.49 per pound of bananas at Smiths

Step-by-step explanation:

1. 10 pounds is $14.90

2. Find how much one pound costs by dividing 14.90 by 10

3. 14.90/10= 1.49

4. $1.49 per pound of bananas at Smiths

6 0

3 years ago

PLEASE JUST THE ANSWER!

LUCKY_DIMON [66]

Answer:

7

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

1/4( -1 + 4)+3/5 please help ME missing work!

nignag [31]

Answer:

1.35

Step-by-step explanation:

I believe this is right but it could be wrong. Hope this helps! <3

3 0

3 years ago

Anyone????????????????????

ser-zykov [4K]

Answer:

4

Step-by-step explanation:

You can use the Pythagorean theorem to find the length of the unknown side.

For that, let the unknown side be x.

Let us solve now.

2² + x² = ( 2√5)²

4 + x² = 2√5 × 2√5

4 + x² = 2 × 2 × √5 × √5

4 + x² = 4 × 5

4 + x² = 20

x² = 20 - 4

x² = 16

x = √16

x = 4

Hope this helps you :-)

Let me know if you have any other questions :-)

6 0

3 years ago

Complete the assignment on a separate sheet of paper Please attach pictures of your work.

Irina18 [472]

Answer:

TO FIND :-

Length of all missing sides.

FORMULAES TO KNOW BEFORE SOLVING :-

$\sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}$
$\cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}$
$\tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}$

SOLUTION :-

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

$=> \sin 16 = \frac{7}{x}$

$=> \frac{7}{x} = 0.27563......$

$=> x = \frac{7}{0.27563....} = 25.39568.....$ ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

$=> \sin 29 = \frac{6}{x}$

$=> \frac{6}{x} = 0.48480......$

$=> x = \frac{6}{0.48480....} = 12.37599.....$ ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

$=> \sin 30 = \frac{x}{11}$

$=> \frac{x}{11} = 0.5$

$=> x = 0.5 \times 11 = 5.5$

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

$=> \cos 43 = \frac{x}{12}$

$=> \frac{x}{12} = 0.73135......$

$=> x = 12 \times 0.73135.... = 8.77624....$ ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

$=> \cos 55 = \frac{x}{6}$

$=> \frac{x}{6} = 0.57357......$

$=> x = 6 \times 0.57357.... = 3.44145....$ ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

$=> \cos 73 = \frac{8}{x}$

$=> \frac{8}{x} = 0.29237......$

$=> x = \frac{8}{0.29237.....} = 27.36242.....$ ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

$=> \tan 69 = \frac{12}{x}$

$=> \frac{12}{x} = 2.60508......$

$=> x = \frac{12}{2.60508....} = 4.60636....$ ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

$=> \tan 20 = \frac{11}{x}$

$=> \frac{11}{x} = 0.36397......$

$=> x = \frac{11}{0.36397....} =30.22225....$ ≈ 30.2

5 0

3 years ago

-16 p + 37 = 49 - 21 p