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3 years ago

Jennifer buys a block of clay for an art project. The block is shaped like a cube with edge lengths of 12 inches.

Mathematics

1 answer:

Gnoma [55]3 years ago

7 0

Answer:

Volume of block Jennifer bought:

V = side^3 = 12 x 12 x 12 = 1728 (in3)

Volume of sphere Jennifer wanted to make:

V = (4/3) x pi x radius^3 = (4/3) x pi x (4/2)^3 = 33.5 (in3)

a, The number of spheres she can make:

N = 1728/33.5 = 51.58 = ~51

b, The area of remaining clay after she made a sphere:

A = 1728 - 33.5 = 1694.5 (in3)

Hope this helps!

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cricket20 [7]

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2 years ago

Shards of clay vessels were put together to reconstruct rim diameters of the original ceramic vessels found at the Wind Mountain

Otrada [13]

Answer:

a) In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)^2}{n-1}}$ (3)

The mean calculated for this case is

The sample deviation calculated $s=3.46 \approx 3.5$

b) $15.8-1.383\frac{3.5}{\sqrt{10}}=14.27$

$15.8+1.383\frac{3.5}{\sqrt{10}}=17.33$

So on this case the 80% confidence interval would be given by (14.27;17.33)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)^2}{n-1}}$ (3)

The mean calculated for this case is

The sample deviation calculated $s=3.46 \approx 3.5$

Part b

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=10-1=9$

Since the Confidence is 0.80 or 80%, the value of $\alpha=0.2$ and $\alpha/2 =0.1$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.1,9)".And we see that $t_{\alpha/2}=1.383$