Read the statement.

Chemistry

2 answers:

AfilCa [17]3 years ago

7 0

Answer : The correct option is, (B) 61 g/L

Explanation :

First we have to calculate the mass of NaCl.

As, 1000 ml NaCl solution contain 4 grams of NaCl

So, 200 ml NaCl solution contain $\frac{200}{1000}\times 4=0.8$ grams of mass of NaCl

Now we have to calculate the mass of another NaCl.

As, 100 ml NaCl solution contain 8 grams of NaCl

So, 600 ml NaCl solution contain $\frac{600}{100}\times 8=48$ grams of NaCl

Total mass of NaCl = 0.8 + 48 = 48.8 g

Total volume of NaCl solution = 200 + 600 = 800 ml

Now we have to calculate the final concentration of salt in the solution.

$Concentration=\frac{\text{Total mass}}{\text{Total volume}}$

$Concentration=\frac{48.8g}{800ml}=0.061g/ml=0.061g/ml\times 1000=61g/L$

Therefore, the final concentration of salt in the solution is, 61 g/L

Pachacha [2.7K]3 years ago

3 0

BRAINLIEST

It is D due to the 200 - 4.0 divided by the 8% of NaCI

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