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ladessa [460]
3 years ago
10

The molar mass of silicon

Chemistry
2 answers:
Yuliya22 [10]3 years ago
7 0
<span>28.0855 u ± 0.0003 u i hopes dis helps you</span>
Norma-Jean [14]3 years ago
4 0
Yes what the guy above me said
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BRAINLIESTTT ASAP!!!! PLEASE ANSWER
Viktor [21]

1. Yes because the ocean takes in the carbon dioxide from the air. This causes more acid in the water, this makes it hard to make shells and skeletons for the seal life that need them.

2.No because it isn't harmful unless it builds up. But there is people who work to clean and limit the chances of build-up.


Hope this helps :)

5 0
3 years ago
Read 2 more answers
2.303 3-5.05x10-3<br> 1 | - 1<br> T2298
bekas [8.4K]

Answer:

230,294.9 I think it's fine just try your past or ask teacher help

6 0
3 years ago
A sample of hydrated magnesium sulfate (MgSO4)
yaroslaw [1]

Answer:

MgSO4.7H2O

Explanation:

Let the formula for the hydrated magnesium sulphate be MgSO4.xH2O

Mass of the hydrated salt (MgSO4.xH2O) = 12.845g

Mass of anhydrous salt (MgSO4) = 6.273g

Mass of water molecule(xH2O) = Mass of the hydrated salt — Mass of anhydrous salt = 12.845 — 6.273 = 6.572g

Now,we can obtain the number of mole of water molecule present in the hydrated salt as follows:

Molar Mass of hydrated salt (MgSO4.xH2O) = 24 + 32 + (16x4) + x(2 + 16) = 24 + 32 + 64 + x(18) = 120 + 18x

Mass of xH2O/ Molar Mass of MgSO4.xH2O = Mass of water / mass of hydrated salt

18x/120 + 18x = 6.572/12.845

Cross multiply to express in linear form

18x x 12.845 = 6.572(120 + 18x)

231.21x = 788.64 + 118.296x

Collect like terms

231.21x — 118.296x = 788.64

112.914x = 788.64

Divide both side by 112.914

x = 788.64 /112.914

x = 7

Therefore the formula for the hydrated salt (MgSO4.xH2O) is MgSO4.7H2O

6 0
3 years ago
what would be the ph of an aqueous solution of sulphuric acid which is 5×10^_5 mol l^_1 in concentration​
guajiro [1.7K]

Answer:

the ph of an aqueous solution of sulphuric acid which is 5*10^5 mol in concentration is basic in nature

6 0
3 years ago
HELPPPP PLEASE ASAP!!!
irina [24]
Answer:

230
     Th
  90

Explanation:

The left side shows the element uranium with mass number 234 (superscript to the left of ths symbol) and atomic mass 92 (subscript to the left of the symbol).

So,  you have to find the mass number and atomic numbers missing on the right side which added to those shown for the helium atom reach 234 and 92.

This the the mathematics:

1) Mass number of U - mass number of He = 234 - 4 = 230 ⇒ the mass number of the missing element is 230.

2) atomic number of U - atomic number of He = 92 - 2 = 90 ⇒ the atomic number of the missing element is 90.

Now, you use the atomic mass to identify the element. You do it by simply searching in a periodic table. There you find that the atomic number 90 corresponds to thorium, whose symbol is Th.

Now you have that the product that completes the right side of the decay equation is:

230
     Th
  90


4 0
3 years ago
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