Answer:
154 g
Explanation:
Step 1: Write the balanced decomposition equation
2 NaN₃(s) ⇒ 2 Na(s) + 3 N₂(g)
Step 2: Calculate the moles corresponding to 79.5 L of N₂ at STP
At STP, 1 mole of N₂ occupies 22.4 L.
79.5 L × 1 mol/22.4 L = 3.55 mol
Step 3: Calculate the number of moles of NaN₃ needed to form 3.55 moles of N₂
The molar ratio of NaN₃ to N₂ is 2:3. The moles of NaN₃ needed are 2/3 × 3.55 mol = 2.37 mol.
Step 4: Calculate the mass corresponding to 2.37 moles of NaN₃
The molar mass of NaN₃ is 65.01 g/mol.
2.37 mol × 65.01 g/mol = 154 g
Inner planets are rockier and outer planets are gaseous. Hope this helps! Can I have brainliest please
CaCO₃ is a compound in and of itself thus it is not a polyatomic ion.
B - CCL4
This is because it doesn't say Dicarbon or any of that sort, so Carbon is alone. This immediately eiminates the option of C.
A is incorrect as it has Chlorine first rather than Carbon, so that's also incorrect.
D is incorrect as 7 is hepta rather than tetra.
The list is as so;
Mono - 1; Di - 2; Tri - 3; Tetra - 4; Penta - 5; Hexa - 6; Hepta - 7; Octa - 8; Nona - 9; Deca - 10.
Hope this helps!
