Answer:
=<em><u> 1.7 M</u></em>
Explanation:
Molecular mass of NaCl = ( 23+35.5 ) = 58.5g
58.5g of NaCl are weighed by 1 mole of NaCl
10.0g of NaCl will be weighed by ( 10÷58.5 )
<em> <u>= 0.17 moles of </u><u>NaCl</u></em>
100mL = ( 100÷1000)L = 0.1L
0.1L of a solution is occupied by 0.17 moles of NaCl
<u>1L</u> of solution will be occupied by [(1÷0.1)×0.17]
=<em><u>1</u></em><em><u>.</u></em><em><u>7</u></em><em><u> </u></em><em><u>M</u></em>
Answer:

Explanation:
Hello there!
In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

Then, we accommodate the waters to obtain:

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hope it helped
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I think it's oxide and halide