<h2>Answer : The order of conductivity from most conductive to least is this - </h2><h2>Calcium bromide
, Potsassium bromide (KBr), Benzoic acid
and last is sugar.</h2><h3>Explanation : </h3>
When dissolved in water produces three ions namely; 
and 
which acts as best conductor amongst the given choices.
Next is potassium bromide when dissolved in water generates only two ions which are 
and 
and acts as an conductor.
Benzoic acid 
, is a weak acid and is slightly ionized so it acts as an weak conductor.
Sugar is a non ionized compound so it is anon conductor.
Answer:
Total mass of original sample = 0.38 g
Explanation:
Percentage of chloride = 74.5%
Mass of AgCl precipitate = 1.115 g
Mass of original sample = ?
Solution:
Mass of chloride:
1.115 g/ 143.3 g/mol × 35.5 g/mol
0.0078 g × 35.5 = 0.28 g
Total mass of compound:
Total mass = mass of chloride / %of Cl × 100%
Total mass = 0.28 g/ 74.5% × 100%
Total mass = 0.0038 g× 100
Total mass = 0.38 g
Answer:
The equilibrium temperature of the coffee is 72.4 °C
Explanation:
Step 1: Data given
Mass of cream = 15.0 grams
Temperature of the cream = 10.0°C
Mass of the coffee = 150.0 grams
Temperature of the coffee = 78.6 °C
C = respective specific heat of the substances( same as water) = 4.184 J/g°C
Step 2: Calculate the equilibrium temperature
m(cream)*C*(T2-T1) = -m(coffee)*c*(T2-T1)
15.0 g* 4.184 J/g°C *(T2 - 10.0°C) = -150.0g *4.184 J/g°C*(T2-78.6°C)
62.76T2 - 627.6 = -627.6T2 + 49329.36
690.36T2 = 49956.96
T2 = 72.4 °C
The equilibrium temperature of the coffee is 72.4 °C
Answer:
H2 is the limiting reactant.
Explanation:
From the diagram above:
H2 => White ball
O2 => Red ball
Before the reaction
H2 => White ball => 10
O2 => Red ball => 7
After the reaction
H2O => White and red ball => 10
O2 => 2
From the simple illustration above, we can see that all the H2 were used up in the reaction but there are left over of O2.
This simply means that H2 is the limiting reactant as all of it is used up in the reaction while O2 is the excess reactant as there are leftover.
