What is the molarity of 10.0 g of NaCl dissolved in water to make 100. mL?
1 answer:
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Explanation:
Force applied on the gas will be as follows.
As, F = pressure × area. Hence, calculate the forces as follows.
= pressure × area
=
= N
= pressure × area
=
= N
-
=
N
Substituting the calculated values into the above formula as follows.
= (m + M) g
N =
N =
m = 472.76 kg
Thus, we can conclude that the mass is 472.76 kg.
Answer:
Determine the pH of the solution half-way to the end-point on the pH titration curve for acetic acid.
Explanation:
The equation for the ionization of acetic acid is
HA + H₂O ⇌ H₃O⁺ + A⁻
For points between the starting and equivalence points, the pH is given by the Henderson-Hasselbalch equation:
At the half-way point, half of the HA has been converted to A⁻, so [HA] = [A⁻]. Then,
The pKₐ is the pH at the half-way point in the titration.
