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olga2289 [7]
3 years ago
7

What does remedy mean

Computers and Technology
2 answers:
Serggg [28]3 years ago
4 0
Remedy means a Medicine or treatment for an injury.
Hope it helps!
Inessa05 [86]3 years ago
4 0
   Remedy-
a medicine or treatment for a disease or injury. :)
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How to convert mkv to avi without losing quality?
Alexus [3.1K]
Ive done this before with success.
You will need <span>FFmpeg.</span>
https://superuser.com/questions/227338/how-to-convert-an-mkv-to-avi-with-minimal-loss
7 0
3 years ago
Suppose that you are asked to modify the Stack class to add a new operation max() that returns the current maximum of the stack
Advocard [28]

Answer:

Following are the code to the given points:

Explanation:

For point 8.1:

public String max()//defining a method max

{

   String maxVal=null;//defining a string variable that holds a value

   for(int x=0;x<n;x++)

   {

       if(maxVal==null || a[i].compareTo(maxVal)>0)//defining if blok to comare the value

       {

           maxVal=a[i];//holding value in maxVal variable

       }

   }

   return maxVal;//return maxVal variable value

}

For point 8.2:

public void push(String item)//defining a method push that accepts item value in a parameter

{

       a[n]=item;//defining an array to hold item value

       if(n==0 || item.compareTo(maxVals[n-1])>0)//use if to comare item value

       {

               maxVals[n]=item;//holding item value in maxVals variable

       }

       else

       {

               maxVals[n]=maxVals[n-1];//decreasing the maxVals value

       }

       n++;//incrementing n value

}

public String pop()//defining a method pop

{

       return a[--n];//use return value

}

public String max()//defining a method max

{

       return maxVals[n-1];//return max value

}

  • In the first point, the max method is declared that compares the string and returns its max value.
  • In the second point, the push, pop, and max method are declared that works with their respective names like insert, remove and find max and after that, they return its value.
7 0
3 years ago
g You and your friend both send documents to the printer, but the printer can only print one document at a time. What does it do
Sedbober [7]

Answer:

It places the document in a buffer

Explanation:

Since the printer can only print a document at a time, the other document is going to be placed in a buffer.

The print buffer can be described as a location in memory that has the function of holding data that is going to be sent to a computers printer. A print job such as in this scenario may remain in the buffer because another document is to be printed first.

Sometimes a document could be put in the buffer because the computer is waiting for the printer to respond. This is just another reason why documents are placed in a buffer.

5 0
3 years ago
How do companies use web sites?
kramer

they us websites to look thing up that are need

hope this helps

5 0
3 years ago
Write a program that first gets a list of integers from input. Then, get another value from the input, and output all integers l
jonny [76]

Answer:

The c++ program for the given scenario is given below.

#include <iostream>

using namespace std;

int main() {

   int len=20, arr[len], data;    

   // initialize all elements of the array to 0

   for(int i=0; i<len; i++)

   {

       arr[i] = 0;

   }    

   cout<<"This program outputs all the numbers less than or equal to the given number."<<endl;

   cout<<"Enter the list of numbers. Enter 0 to stop entering the numbers. "<<endl;

   for(int i=0; i<len; i++)

   {

       cin>>arr[i];        

       // 0 indicates user wishes to stop entering values  

       if(arr[i] == 0)

           break;

       else

           continue;

   }    

   // number from which the list is to be compared

   cout<<"Enter the number to be compared."<<endl;

   cin>>data;

     

   cout<<"The values less than or equal to the number "<<data<<" are "<<endl;

   for(int i=0; i<len; i++)

   {  

       // 0 indicates the end of the list entered by the user

       if(arr[i]==0)

           break;

       if(arr[i] <= data)

           cout<<arr[i]<<endl;

   }    

   return 0;    

}  

OUTPUT

This program outputs all the numbers less than or equal to the given number.

Enter the list of numbers. Enter 0 to stop entering the numbers.  

23

45

67

89

10

0

Enter the number to be compared.

59

The values less than or equal to the number 59 are  

23

45

10

Explanation:

This program takes input only from the user and makes no assumptions.

The list of numbers entered by the user are stored in an array. If the user input is less than the size of the array, the remaining elements are set to 0.

While taking input from the user, if any element of the array is found to be 0, the loop is discontinued.

for(int i=0; i<len; i++)

   {

       cin>>arr[i];        

       if(arr[i] == 0)

           break;

       else

           continue;

   }  

Same test is applied when all the numbers less than the given number are displayed.

for(int i=0; i<len; i++)

   {  

        if(arr[i]==0)

           break;

       if(arr[i] <= data)

           cout<<arr[i]<<endl;

   }

The above program takes into account all the specifications in the given question.

5 0
3 years ago
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