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Anika [276]
3 years ago
9

BRAINLIESTT ASAP! PLEASE HELP ME :)

Mathematics
2 answers:
myrzilka [38]3 years ago
7 0
Circumference is 25.13
area is 50.27
spin [16.1K]3 years ago
6 0
<h3>Answers:</h3><h3>Exact area = 16pi   square meters</h3><h3>Exact circumference = 8pi    meters</h3>

Note how the units are not the same for each. The area involves square units while the circumference is a linear unit.

==========================================================

Work Shown:

d = 8 is the diameter

r = d/2 = 8/2 = 4 is the radius

A = area of circle

A = pi*r^2

A = pi*4^2

A = pi*16

A = 16pi

---------

C = circumference of the circle

C = pi*d

C = pi*8

C = 8pi

Alternatively,

C = 2*pi*r

C = 2*pi*4

C = 2*4*pi

C = 8pi

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The lengths of two sides of a triangle are 5 and
Gwar [14]

Answer:

D) 2

Step-by-step explanation:

A Triangle two sides added together must always be greater than the other side.

It can not be 2 because the two sides of a triangle added are not greater than the other side.

Here 5 + 2 = 7 which is not greater than 7 on the other side, so 2 fails.

5 0
2 years ago
The cost of a bag of 8 peaches is $16. You could also buy individual peaches for
Veronika [31]

Answer: The peaches sold in bags

Step-by-step explanation:

16/8=2 This means that a single peach in the bag of peaches is worth $2. This is $0.15 cheaper than buying a single peach

The unit rte for a single peach is $2.15

The unit rate for a single peach in the bag of peaches is $2

5 0
3 years ago
1. The chart below represents the percentage of Americans traveling to each destination.
lidiya [134]
B 23%
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7 0
3 years ago
Determine the most specific name for the figure in the diagram.
Makovka662 [10]
<span>ABCD is a parallelogram. Looking at the quadrilateral ABCD, the first thing to do is to determine if the opposite sides are parallel to each other. So let's check that by looking at the opposite sides. Line segment BA. When you go from point B to point A, you move to the right 1 space, and down 4 spaces. So the slope is -4. Looking at line segment CD, you also move to the right 1 space and down 4 spaces, which also means a slope of -4. So those two sides are parallel. When you compare line segments BC and AD, you'll notice that for both of them, you go to the right 5 spaces and up 2 spaces, so those too are parallel. So we can now saw that the quadrilateral ABCD is a parallelogram. Since ABCD is a parallelogram, we now need to check if it's a rectangle (we know it can't be a square since the sides aren't all the same length). An easy way to test if it's a rectangle is to check of one of the angles is 90 degrees. And if we draw a line from B to D, we can create a triangle ABD. And in a right triangle, due to Pythagora's theorem we know that A^2 + B^2 = C^2 where A is the line segment AB, B is the line segment AD and C is the line segment BD. So let's calculate A^2, B^2, and C^2. A^2: Line segment AB. We can construct a right triangle with A = 1 and B = 4. So C^2 = 1^2 + 4^2 = 1 + 16 = 17. So we have an A^2 value of 17 B^2: Line segment AD. We can construct a right triangle with A = 2 and B = 5. So C^2 = 2^2 + 5^2 = 4 + 25 = 29. So we have an B^2 value of 29 C^2: Line segment BD. We can construct a right triangle with A = 2 and B = 6. So C^2 = 2^2 + 6^2 = 4 + 36 = 40. So we have a C^2 value of 40. Now let's check if the equation A^2 + B^2 = C^2 is correct: 17 + 29 = 40 46 = 40 And since 46 isn't equal to 40, that means that ABCD can not be a rectangle. So it's just a parallelogram.</span>
6 0
3 years ago
Which of the following is the equation for the graph shown?a. x^2/144+y^2/95=1b. x^2/144-y^2/95=1c. x^2/95+y^2/144=1d. x^2/95-y^
Andrews [41]

e follSOLUTION

Given the question in the image, the following are the solution steps to answer the question

STEP 1: Write the general equation of an ellipse

\frac{\mleft(x-h\mright)^2}{a^2}+\frac{(y-h)^2}{b^2^{}}=1

STEP 2: Identify the parameters

the length of the major axis is 2a

the length of the minor axis is 2b

\begin{gathered} 2a=24,a=\frac{24}{2}=12 \\ 2b=20,b=\frac{20}{2}=10 \end{gathered}

STEP 3: Get the equation of the ellipse

\begin{gathered} By\text{ substitution,} \\ \frac{(x-h)^2}{a^2}+\frac{(y-h)^2}{b^2}=1 \\ \frac{(x-0)^2}{12^2}+\frac{(y-0)^2}{10^2}=1=\frac{x^2}{144}+\frac{y^2}{100}=1 \end{gathered}

STEP 4: Pick the nearest equation from the options,

Hence, the equation of the ellipse in the image is given as:

\frac{x^2}{144}+\frac{y^2}{95}=1

OPTION A

8 0
1 year ago
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