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mrs_skeptik [129]
3 years ago
15

What is 8(c-9)=6(2c-12)-4c? Solve for c. Please show your work.

Mathematics
1 answer:
Dafna11 [192]3 years ago
4 0

Answer:

c= ℝ

Step-by-step explanation:

8(c-9)=6(2c-12)-4c

Distribute left side.

8*c+8*-9=6(2c-12)-4c

8c-72=6(2c-12)-4c

Distribte right side.

8c-72=6*2c+6*-12-4c

8c-72=12c-72-4c

Combine like terms.

8c-72=8c-72

Since the two sides are exactly the same, this means that any number for c will satisfy the equation.

Therefore, c= ℝ (all real numbers)

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4 0
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What are the restrictions for a? 2a^2+a-15/5a^2+16a+3
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ANSWER


The restrictions are

a\ne -3,a\ne -\frac{1}{5}


EXPLANATION


We were given the rational function,


\frac{2a^2+a-15}{5a^2+16a+3}


The function is defined for all values of a, except



5a^2+16a+3=0


This has become a quadratic trinomial, so we need to split the middle term.


We do that by multiplying the coefficient of x^2 which is 5 by the constant term which is 3. This gives us 15.


The factors of 15 that adds up to 16 are 1 and 15.


We use these factors to split the middle term.




5a^2+15a+a+3=0


We now factor to get,


5a(a+3)+1(a+3)=0


We factor further to get,


(a+3)(5a+1)=0



This implies that,


(a+3)=0,(5a+1)=0


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a=-3,a=-\frac{1}{5}


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Step-by-step explanation:

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