Protons = +1
negatrons = -1
neutrons = 0
<span>electrons = -1
</span>
<span>negatrons are like positrons and they are subatomic particles and are not present in atoms
</span>
so electrons are negatively charged and are present in atoms
hope that helps
Answer and Explanation:
The molar mass of a substance is all of the weights from the elements combined.
So, we have the elements
CU, S, and 
CU has a mass is 65
S mass is 32
O has a mass of 16, but there's 4 atoms of O, so we do 16 times 4, which is 64.
Now we add.
65 + 32 + 64 is 161.
<u>So, the answer is 160, or answer choice A.</u>
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
Answer: the percentage of acetic acid will be low.
Explanation: The major aim during titration of acids and bases is to determine the endpoint , that is exact point where the acid in the beaker changes colour, (in this case, pink )with an additional drop from the burette containing the base, since it is usually difficult to mark the equivalence point that tells us when all the substrate in the beaker has been neutralized completely with the buretted substance.
Overshooting the end point is an error which can occur when the person involved in the the titration accidently goes beyond this endpoint by adding too much of the substance(base) from the burette into the beaker missing the exact endpoint.
This implies that the person has added too much of the burreted liquid, ie the base than required , making the acid in the beaker to continue to react resulting to a lower concentration of the acid (acetic acid) with excess base.(NaOH)
Answer:
a and b are correct
Explanation:
This because both are aqueous solutions,therefore, identity of solvent is same that is water.
And because both solutions are non electrolyte they would not ionize in solution, and for the same concentration, the freezing point of both solution would also be same. Since depression in freezing point is a colligative property this means that it depends on number of solute particles not nature of particles
.
Hence answer is that their freezing points and Identity of the solvent shall remain the same.
