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tatiyna
3 years ago
5

You wish to analyze the purity of a compound via TLC. If you wanted polar compounds to remain near the bottom (baseline) of the

plate, what kind of TLC plate would you use? (1 pt)
Chemistry
1 answer:
nikklg [1K]3 years ago
7 0

Options:

A reverse phase TLC plate because the nonpolar stationary phase will interact with polar compounds more strongly.

A normal phase TLC plate because the polar stationary phase will interact with polar compounds more strongly.

A reverse phase TLC plate because the polar stationary phase will interact with polar compounds more strongly.

A normal phase TLC plate because the nonpolar stationary phase will interact with nonpolar compounds more strongly.

Answer:A normal phase TLC plate because the polar stationary phase will interact with polar compounds more strongly.

Explanation:TLC(THIN LAYER CHROMATOGRAPHY) is a solid (stationary phase) and a liquid(mobile phase) technique of separation and purity determination that uses the principle of that different compounds have different adsorption rate and different solubility rate to the two phases between which they are partitioned.

ON A DEVELOPED THIN LAYER CHROMATOGRAPHIC PLATE A PURE COMPOUND WILL APPEAR ONLY ON ONE SPOT.

With TLC one can analyse multiple samples at the same time.

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36.8 g of CuSO4(s) was added to water to prepare a 2.00 L solution. What is the
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Answer:

Option D. 0.115 M

Explanation:

The following data were obtained from the question:

Mass of CuSO4 = 36.8 g

Volume of solution = 2 L

Molar mass of CuSO4 = 159.62 g/mol

Molarity of CuSO4 =..?

Next, we shall determine the number of mole in 36.8 g of CuSO4.

This can be obtained as shown below:

Mass of CuSO4 = 36.8 g

Molar mass of CuSO4 = 159.62 g/mol

Mole of CuSO4 =.?

Mole = mass /Molar mass

Mole of CuSO4 = 36.8 / 159.62

Mole of CuSO4 = 0.23 mole

Finally, we shall determine the molarity of the CuSO4 solution as illustrated below:

Mole of CuSO4 = 0.23 mole

Volume of solution = 2 L

Molarity of CuSO4 =..?

Molarity = mole /Volume

Molarity of CuSO4 = 0.23 / 2

Molarity of CuSO4 = 0.115 M

Therefore, the molarity of the CuSO4 solution is 0.115 M.

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4 years ago
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Answer:

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Explanation:

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B is incorrect because that only applies to nuclear fission.

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