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2 years ago

Which of the following substances has the highest melting point?

Chemistry

1 answer:

Aleksandr [31]2 years ago

5 0

Nonane (b) has the highest melting point.

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A caveat: I'm assuming that we're dealing with the straight-chain isomers of these alkanes (specifically pentane and nonane). The straight-chain isomer of pentane (n-pentane, CH3-[CH2]3-CH3) has a melting point of -129.8 °C; the straight-chain isomer of nonane (n-nonane, CH3-[CH2]7-CH3) has a melting point of -53.5 °C. The pattern holds as you go down (or up): The more carbon atoms, the higher the melting point. So, in decreasing order of melting points here, you'd have the following: nonane > pentane > butane > ethane.

However, one structural isomer of pentane, neopentane, has a melting point of -16.4 °C, which is higher that the melting point of n-nonane despite neopentane having the same molecular formula as its straight-chain isomer. Of course, you're not to blame for coming up with this question; this is just some extra info to keep in mind.

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What does scientific inquiry refer to

Sloan [31]

It refers to the ways scientists explore and study the world based on observations and their works/ evidence.

5 0

2 years ago

Charge on proton is?

QveST [7]

Answer:

positive

Explanation:

proton is a subatomic particle with a postive charge on it.

hope this helps!!! ☺️

7 0

3 years ago

Read 2 more answers

A 33.0 mL sample of 1.15 M KBr and a 59.0 mL sample of 0.660 M KBr are mixed. The solution is then heated to evaporate water unt

Oksi-84 [34.3K]

Answer:

We need 13.06 grams of silver nitrate to precipitate out silver bromide in the final solution

Explanation:

Step 1: Data given

Sample 1: The 1.15 M sample has a volume of 33.O mL

Sample 2: The 0.660 M sample has a volume of 59.0 mL

Molar mass of KBr = 119 g/mol

Molar mass of AgNO3 = 169.87 g/mol

Step 2: Calculate number of moles for both samples

Number of moles = Molarity * Volume

Sample 1: 1.15 M * 33 *10^-3 L = 0.03795 moles

Sample 2: 0.660 M *59*10^-3 L = 0.03894 moles

Total mol KBr = 0.03795 + 0.03894 = 0.07689 moles

Step 3: Calculate total mass

mass = Number of moles * Molar mass

mass = 0.07689 moles * 119 g/moles = 9.15 grams ( in 55mL)

Step 4: Calculate moles of AgBr

AgNO3 reacts with KBr

KBr(aq) + AgNO3(aq) → AgBr(s) + KNO3(aq)

1 mole of KBr consumed, needs 1 mole of AgNO3 to produce 1 mole of AgBr and 1 mole of KNO3

So 0.07689 moles of KBr wll need 0.07689 moles of AgNO3

Step 5: Calculate mass of silver nitrate

mass of AgNO3 = Moles of AgNO3 * Molar mass of AgNO3

mass of AgNO3 = 0.07689 moles * 169.87 g/mol = 13.06 grams

We need 13.06 grams of silver nitrate to precipitate out silver bromide in the final solution

8 0

3 years ago

Consider the synthesis of ammonia 3 H2+ N2 à 2 NH3 If a student were to react 38.5 g of nitrogen gas, how many moles of ammonia

Wittaler [7]

Answer:

2.75 mol

Explanation:

Given data:

Mass of Nitrogen = 38.5 g

Moles of ammonia produced = ?

Solution:

Chemical equation:

N₂ + 3H₂ → 2NH₃

Number of moles of nitrogen:

Number of moles = mass/ molar mass

Number of moles = 38.5 g/ 28 g/mol

Number of moles = 1.375 mol

Now we will compare the moles of ammonia and nitrogen from balance chemical equation.

N₂ : NH₃

1 : 2

1.375 : 2×1.375 = 2.75 mol

Thus 2.75 moles of ammonia are produced from 38.5 g of nitrogen.

4 0

2 years ago

Now examine salts containing the halide anions, cl- and br-. Most of these are soluble. What two cations listed lead to insolubl

tatiyna

Ag+ and Pb+2 are two cations that are suggested as producing insoluble halide salts when studying salts containing the halide anions, cl- and br-. First, the charge's number is provided.

Neutral binary salts, also referred to as halide salts, are mixtures of metals and non-metals. The non-metal behaves in a reduced oxidation state at all times. They are the outcome of mixing a hydroxide and hydracid. halide salts of haloids are produced by the reaction of a hydroxide and a hydracid.

Ions are cations with positive charges. They emerge when the electrons of an elemental metal are lost. However, they don't lose any protons; they only lose one or more electrons. To denote a cation, the charge is superscripted following the element name or chemical formula.

Learn more about halide salts here

brainly.com/question/20815131

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8 0

1 year ago