Answer:
Van't Hoff factor for AlCl₃ = 3 (Approx)
Explanation:
Given:
Number of observed particular = 1.79 M
Number of theoretical particular = 0.56 M
Find:
Van't Hoff factor for AlCl₃
Computation:
Van't Hoff factor for AlCl₃ = Number of observed particular / Number of theoretical particular
Van't Hoff factor for AlCl₃ = 1.79 M / 0.56 M
Van't Hoff factor for AlCl₃ = 3.19
Van't Hoff factor for AlCl₃ = 3 (Approx)
The answers that fit the blanks are SMALL and LITTLE, respectively. The particles or molecules or fas are small which makes it loose and easily moves around, and these only exert little attraction for other gas particles. The answer for this would be option D.
The ion is Al³⁺
mass number - number of neutrons= atomic number
27 - 14 = 13
Aluminum has an atomic number of 13, thus we know this is the metal in question. Also, because the aluminum has only 10 electrons, (3 less than a neutral atom of aluminum would have), its charge must be 3+
A measure of thermal energy transferred between two different bodies at different temperatures would be the correct answer. So, the third option.
The steam releases 39.9 kJ when it condenses..
The steam condenses and transfers its energy to the skin.
<em>q = m</em>Δ<em>H</em>_cond = 17.7 g × (-2257 J/1 g) = -39 900 kJ = -39.9 kJ
The negative sign shows that the steam is releasing energy
