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AVprozaik [17]
3 years ago
14

PLEASE HELPP ______ consist of one large main root with smaller roots branching off, while _____ consist of several main roots t

hat branch off to form one. mass of roots. Question 3 options: taproots; fibrous roots fibrous roots; taproots stems; leaves leaves; stems
Chemistry
1 answer:
Kay [80]3 years ago
6 0

fibrous roots; taproots

Explanation:

A taproot root consists of one large main root with smaller roots that branches off into the soil, while the fibrous roots consists of several main roots that branches off to form one mass of roots.

  • The root system in plants helps them to absorb water and other nutrients from the soil.
  • A taproot is much more like extension of stem that penetrates into the ground.
  • It tapers at the end with many other smaller roots branching and networking from it.
  • The fibrous root is a series of roots directly from the stem that independent of one another.
  • Roots are used by plants for anchorage into the soil.

learn more:

Seedless vascular plants brainly.com/question/6047633

#learnwithBrainly

You might be interested in
Which type of reaction is Pb(NO3)2 + 2HCl → PbCl2 + 2HNO3?
Ganezh [65]

Answer:- D. Double- replacement reaction

Explanations:- In general, the decomposition reactions looks like:

AB\rightarrow A+B

The given reaction looks different than this and so it is not decomposition reaction.

A single-replacement reaction looks like:

AB+C\rightarrow AC+B

Our reaction looks different from this so single-replacement is also not correct.

Synthesis reaction looks exactly opposite to decomposition reaction.

A+B\rightarrow AB

The given reaction is different than this and so it is not synthesis reaction also.

A double-replacement reaction looks like:

AB+CD\rightarrow AD+CB

In this reaction, the ions are exchanged as could be seen in the general reaction. On reaction side,A is with B and C is with D. On product side, A is with D and C is with B.

The same is happening in the given reaction. Nitrate ion is with lead metal on reactant side and chlorine is with hydrogen, On product side, Chlorine is with lead metal and nitrate ion is with hydrogen. So, ion exchange has taken place here and so this is a double-replacement reaction and choice D is correct.

4 0
3 years ago
Using the formula velocity = distance/time, how fast does sound travel in air at 20 degrees C given a distance of 500 m and 3.92
mixas84 [53]

Answer:

B : 127m/s

Explanation:

= 500 ÷ 3.92

= 127.5

5 0
3 years ago
The compound IF5 contains Question 16 options: polar covalent bonds with partial negative charges on the F atoms. ionic bonds. p
larisa86 [58]

Answer:

See explanation

Explanation:

The molecule IF5 possesses five I-F polar bonds. However, the presence of polar bonds does not automatically imply that the molecule will be polar.

The geometry of the molecule is very important in determining the polarity of a compound. Since IF5 has a lone pair of electrons, the molecule is bent and as such there is a permanent dipole moment created in the molecule thereby making IF5 polar in nature.

6 0
3 years ago
trace amounts of copper are required for good healt.but high concentrations of copper can be toxic.under what conditions might t
Andru [333]
For example, at atmospheric corrosion of copper:
2Cu + CO₂ + O₂ + H₂O = CuCO₃*Cu(OH)₂

and disolution of substances of copper in an acid condition:
CuCO₃*Cu(OH)₂(s) + 4HNO₃(aq) = 2Cu(NO₃)₂(aq) + CO₂(g) + 3H₂O(l)
CuCO₃*Cu(OH)₂(s) + 4H⁺ = 2Cu²⁺ + CO₂ + 3H₂O
3 0
3 years ago
3350 J of heat is required to raise the temperature of a sample of AlF3 from 250C to 800C. What is the mass of the sample?
Aleonysh [2.5K]

Answer:

  1. Look up the specific heat capacity of AlF₃
  2. Calculate ΔT
  3. Calculate the mass of AlF₃

Explanation:

The formula for for the heat (q) absorbed by an object is

 q = mCΔT, where

m = the mass of the sample

 C = the specific heat capacity of the sample. and

ΔT = the change in temperature

1. What you must do

  • Look up the specific heat capacity of AlF₃
  • Calculate ΔT
  • Calculate the mass of AlF₃

2. Sample calculation

For this example, I assume that the specific heat capacity of AlF₃ is 1.16 J·K⁻¹mol⁻¹ .

(a) Calculate ΔT  

\Delta T = T_{\text{f}} - T_{\text{i}} = 800 \, ^{\circ}\text{C} -250 \, ^{\circ}\text{C} = 550 \, ^{\circ}\text{C}

(b) Calculate m

\begin{array}{rcl}\text{3350 J} & = & m \times 1.16 \text{ J}\cdot\text{K}^{-1} \text{mol}^{-1}\times \text{550 K}\\3350 & = & m \times \text{638 g}^{-1}\\m & = &\dfrac{3350}{\text{638 g}^{-1}}\\\\ & = & \text{ 5.2 g}\\\end{array}\\

6 0
3 years ago
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