<span>3⋅2−3⋅0.9h+1.3h−4⇒</span>
<span>6−2.7h+1.3h−4⇒</span>
<span>6−4−2.7h+1.3h⇒</span>
<span>2−1.4<span>h</span></span>
<span><span>This is the answer.</span></span>
Circumference = 2(pi)(r)
14 = 2(pi)(r)
14/2pi = r
7pi = radius
diameter = 2r
diameter = 14pi
Lets try
centimeter is about 1/2 of a inch
if 28 square cm, the book coould be about 4m by 7cm (aoub the size of a recipt)
if 28 square in the book could be about 4in by 7in (regular size)
I would guess 28 square INCHES (cm is too smal)
Answer:
The 95% confidence interval for the mean breaking weight for this type cable is (767.47 lb, 777.13 lb).
Step-by-step explanation:
Our sample size is 41
The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

Then, we need to subtract one by the confidence level
and divide by 2. So:

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 40 and 0.025 in the two-sided t-distribution table, we have 
Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

Now, we multiply T and s

Then
The lower end of the confidence interval is the mean subtracted by M. So:

The upper end of the confidence interval is the mean added to M. So:

The 95% confidence interval for the mean breaking weight for this type cable is (767.47 lb, 777.13 lb).