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lions [1.4K]
3 years ago
8

Toyota campy sold 20,600 in 2008. percent change is 1.2%. how many sold in 2009?

Mathematics
1 answer:
Artyom0805 [142]3 years ago
6 0
So 20600=100%
in 2009=1.2% change from 100%

not specific whether percent change is up or down so solve fo r1.2%
d
find 1.2% of 100
percent means parts out of 1001.2%=1.2/100=0.12/10=0.012/1=0.012

'of' means multiply
20600 times 0.012=276.2

the change is 276.2

20600-276.2=20352.8
20600+276.2=20847.2
you must round down since you can't sell 0.2 or 0.8 of a car

the sold either 20,352 or 20,847 cars in 2009

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Ac is tangent to circle o at point c what is the length of ac?
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A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas
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Answer:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

P(A) = 0.8, P(B) = 0.2

We are assuming that the two events are independent so then we have the following propert:

P(A \cap B ) = P(A) * P(B)

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P(B' \cup A')

And using the De Morgan laws we know that:

(A \cap B)' = A' \cup B'

So then we can write the probability like this:

P(B' \cup A') = P((A \cap B)')

And using the complement rule we can do this:

P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)

Since A and B are independent we have:

P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32

And then our final answer would be:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

5 0
3 years ago
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