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3 years ago

Whats the formula to Reed's fence is 96 feet long how many yards long is Reed's fence

1 answer:

8 0

If there are 3 feet per yard, then all you have to do is take the 96 feet and divide by 3, this gives you 32 yards.

If you have any questions please let me know, other wise take care. (:

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Pre-algebra

Vladimir79 [104]

Write down the numbers in the chart, write them on a number line, put a point on the number farthest from 0, Closer

4 0

3 years ago

Read 2 more answers

F(x) = 2x2 + 12x + 1<br> Determine the vertex

Gnom [1K]

Answer:

Step-by-step explanation:

The vertex would be the highest/lowest point so lets factor this first

when we factor we get

2(x^2+6x+8)

2(x+4) (x+2)

Using zero product property we find the 2 x values and x intercepts are

-4 and -2

the middle point of these points is -3

Substitute -3 for x and solve

2(-3+4) (-3+2)

2 * 1 * -1

2*-1

-2

(-3,-2) is the vertex

5 0

3 years ago

How do you solve:<br> 3/4(5+8y)

Veronika [31]

Answer:

15/4 +6y

Step-by-step explanation:

See Image below:)

3 0

3 years ago

In a particular region, for families with a combined income of $75,000 or more, 15% of these families have no children, 35% of t

SCORPION-xisa [38]

Answer:

The probability distribution for x:"number of children per family for this income group" is:

$\text{P(x=0)}=0.15\\\\\text{P(x=1)}=0.35\\\\\text{P(x=2)}=0.45\\\\\text{P(x=3)}=0.05\\\\$

Step-by-step explanation:

With the information given we have the relative frequencies of each category.

We know:

$\text{P(x=0)}=0.15\\\\\text{P(x=1)}=0.35\\\\\text{P(x=2)}=0.45\\\\\text{P(x=3)}=0.05\\\\$

7 0

3 years ago

A growing farming conglomerate increases its water usage at a rate of 5% every year. If it used 48,000 megaliters of water this

romanna [79]

Answer:

Future requirement of water = 115,517 mega-liters

Step-by-step explanation:

Given:

Current requirement of water (C) = 48,000 mega-liters

Increasing rate per year (g) = 5% = 0.05

Number of year (n) = 18 years

Find:

Future requirement of water = ?

Computation:

$Future\ requirement\ of\ water = C(1+g)^n\\\\Future\ requirement\ of\ water = 48,000(1+0.05)^{18}\\\\ Future\ requirement\ of\ water = 48,000(1.05)^{18}\\\\ Future\ requirement\ of\ water = 48,000(2.4)\\\\Future\ requirement\ of\ water = 115,517 (Approx)$

Future requirement of water = 115,517 (Approx) mega-liters

7 0

3 years ago