A slow boat to china travels at a constant speed of 17.25 miles per hour for 200 hours. how far was the voyage?
2 answers:
Answer:
Step-by-step explanation:
Distance can be found by multiply the speed by the time.
Where <em>d</em> is the distance, <em>s</em> is the speed, and <em>t</em> is the time.
1. Define Variables
The speed is 17.25 miles per hour and the time is 200 hours.
2. Calculate Speed
Substitute the values into the formula.
Multiply. The hours (hr) will cancel each other out and leave miles as the units.
The voyage was <u>3,450 miles</u>
You might be interested in
Answer: 26.8 feet
Step-by-step explanation:
In the figure attached you can see two right triangles triangle ABD and a triangle ACD.
You are located at point B and the other person at point C.
The approximate height of the lifeguard station is <em>x</em>.
Keep on mind that:
Therefore:
<em>For the triangle ABD</em>:
[EQUATION 1]
<em>For the triangle ACD:</em>
[EQUATION 2]
Solve from DC from [EQUATION 2]:
Substitute into [EQUATION 1] and solve for x:
≈26.8ft
Hello Meggieh821, to find the lim as x approaches 0 we can check this by inserting a number that is close to 0 that is coming from the left and from the right.
For instance, we can find the lim by using the number -.00001 for x and solve
<span>csc(3x) / cot(x)
</span>csc(3*-.00001) / cot(-.00001) = .333333... = 1 /3
We also need to check coming from the right. We will use the number .00001 for x
csc(3x) / cot(x)
csc(3*.00001) / cot(.00001) = .333333... = 1 /3
So since we are getting 1/3 from the left and right we can say as x approaches 0 the limit is 1/3
<span>
</span>
For instance, we can find the lim by using the number -.00001 for x and solve
<span>csc(3x) / cot(x)
</span>csc(3*-.00001) / cot(-.00001) = .333333... = 1 /3
We also need to check coming from the right. We will use the number .00001 for x
csc(3x) / cot(x)
csc(3*.00001) / cot(.00001) = .333333... = 1 /3
So since we are getting 1/3 from the left and right we can say as x approaches 0 the limit is 1/3
<span>