(10(1-(1/2)^5)/1-(1/2) =
20(1-1/32)
=155/8
If we have two points;
A(x₁,y₁)
B(x₂,y₂)
m=slope
m=(y₂-y₁) / (x₂-x₁)
Therefore:
(6,7)
(9,2)
m=(2-7) / (9-6)=-5/3.
Solution₁= the solpe of the line that passes through the poitns (6,7) and (9,2) is m=-5/3.
(17,9)
(5,29)
m=(29-9) / (5-17)=20/-12=-5/3
Solution ₂: the slope of the line that passes through the parir of points (17,9) and (5,29) is m=-5/3
Therefore, both lines have the same slope.
2-7x +10 =6
2-7(-2)+10
2-14+10
-16+10
-6
PEMDAS
Answer:
5(a+4)
Step-by-step explanation:
expression is equivalent to 5a+20
To get the equivalent expression we need to factor the given expression
5a+ 20
5a can be written as 5 * a
20 can be written as 5*2*2
WE can see that common factor is 5 for both 5a and 20
So GCF is 5
Now we factor out GCF 5
WE put 5 outside and write all the left of factors inside the parenthesis
5a +20
5 (a+2*2)
5(a+4)
Answer:
15
Step-by-step explanation: