Answer:Put an open dot there on top of -1 then point an arrow to the left
Step-by-step explanation:
Answer:
23 Dimes and 8 Quarter.
Step-by-step explanation:
Important info:
31 Coins worth a total of $4.30
Note:
Dimes = .10
Quarters = .25
10 Dimes = 1.00
4 Quarter = 1.00
Question to Answer:
How many of each type of coin does she have?
Solution:
Lets get rid of the .30 cent in $4.30 so
.30 = 3 Dimes
Now $4.00,
4.00-1.00 of quarter
=
3.00 and 4 quarter..
Right now we have 3 Dimes and 4 Quarter = $1.30.
And that 7 Coins worth of $1.30.
3.00-2.00= 1.00 and 20 Dimes so now we have
23 Dimes and 4 Quarter.
And that add up to 27.
1.00-1.00 of Quarter = 4 Quarter.
so 31 worth a total of $4.30.
So that's 23 Dimes and 8 Quarter.
Check Work:
23 Dimes = $2.30 and 8 Quarter = $2.00
$2.30 + $2.00 = 4.30
Hence, The Correct Answer is 23 Dimes and 8 Quarter.
~[ RevyBreeze }~
Answer:
7
Step-by-step explanation:
As you can see, each time (let's say n) increases by 1, it divides by 1/2. So from a1 to a2, you get 28/2 or 14, then from a2 to a3, 14/2 or 7.
7 being your answer.
Answer: The number is: "2 " .
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Explanation:
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Write the expression; which is an equation, as follows:
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" 4x <span>− 12 = 2(-x) " ; in which "x" represents "the number for which we shall solve" .
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Note:
If the "number" = "x" ; the "opposite of the number" = " -x " ;
</span>___________________________________________
Rewrite as: " 4x <span>− 12 = -2x " ;
</span>_____________________________________________
→ Add "12" ; & add "2x" ; to EACH SIDE of the equation:
4x − 12 + 12 + 2x = -2x + 12 + 2x ;
to get: 6x = 12 ;
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Now, divide each side of the equation by "6" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
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6x / 6 = 12 / 6 ;
to get: x = 2 .
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Answer: The number is: "2 " .
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Let us check our answer, by plugging in "2" for "x" in our original equation:
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→ " 4x − 12 = 2(-x) " ;
Let us plug in "2" for "x" ; to see if the equation holds true; that is; if both side of the equation are equal; when "x = 2" ;
→ " 4(2) − 12 = ? 2(-2) ??
→ 8 − 12 = ? -4 ? ;
→ -4 = ? -4 ?? Yes!
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