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3 years ago

(NEED HELP URGENTLY) Similarity and the Pythagorean Theorem

Mathematics

2 answers:

Elena-2011 [213]3 years ago

5 0

x should be 180 I think

Sliva [168]3 years ago

4 0

If v to y is 22, I suppose x equals 44.

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I need the answer and how to do it

irga5000 [103]

You turn 1/3 into 2/6. Because you need the bottom number to match. 3x2=6 then you do the same to the top. 1x2=2. So your answer would be 4/6 but reduced it would be 2/3

3 0

3 years ago

What are the first 2 steps in solving a radical equation

padilas [110]

1-) isolate the radical symbol on one side of the equation

2-) square both sides of the equation to eliminate the radical symbol

5 0

4 years ago

Alvin ordered his dog a bone for $4.45 and a bag of food for $16.30 on Petco.com. The sales tax was 8.65% and there is a $8 deli

DENIUS [597]

Answer:

He spent $30.54

Step-by-step explanation:

$4.45+$16.30=$20.75

$20.75 times 1.0865=$22.544875 rounded to 2 d.p. = $22.54

$22.54+$8=$30.54

8 0

3 years ago

can some one explain how to get the answer to this : the record for the most amount of rain in the shortest periodontal time in

Vlad [161]

Do 42 divided by 15 then divided 12 by the awnser. And you do 42 divided by 28 and divided that by 12 I think I'm pretty sure

8 0

3 years ago

According to the Rational Root Theorem, which number is a potential root of f(x) = 9x8 + 9x6 – 12x + 7?

AysviL [449]

Answer:

$\pm 1, \pm\dfrac{1}{3},\pm\dfrac{1}{9},\pm 7, \pm\dfrac{7}{3},\pm\dfrac{7}{9}$ .

Step-by-step explanation:

According to the Rational Root Theorem, the potential roots of a polynomial are

$x=\pm\dfrac{p}{q}$

where, p is a factor of constant and q is a factor of leading term.

The given polynomial is

$f(x)=9x^8+9x^6-12x+7$

Here, 9 is the leading term and 7 is constant.

Factors of 9 are ±1, ±3, ±9.

Factors of 7 are ±1, ±7.

Using rational root theorem, the rational or potential roots are

$x=\pm 1, \pm\dfrac{1}{3},\pm\dfrac{1}{9},\pm 7, \pm\dfrac{7}{3},\pm\dfrac{7}{9}$

Therefore, the potential root of f(x) are $\pm 1, \pm\dfrac{1}{3},\pm\dfrac{1}{9},\pm 7, \pm\dfrac{7}{3},\pm\dfrac{7}{9}$ .

4 0

3 years ago

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