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sergij07 [2.7K]
3 years ago
10

How do I evaluate |4/18| ?

Mathematics
1 answer:
marysya [2.9K]3 years ago
4 0

Answer:

Step-by-step explanation:

Note*


To evaluate an expression, we substitute the given number for the variable in the expression and then simplify the expression using the order of operations. To evaluate, substitute 3 for x in the expression, and then simplify.

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A 2-column table with 6 rows. Column 1 is labeled x with entries 8, 12, 16, 20, 25, 28. Column 2 is labeled y with entries 2, 3,
podryga [215]

Step-by-step explanation:

A 2-column table with 6 rows. Column 1 is labeled x with entries 8, 12, 16, 20, 25, 28. Column 2 is labeled y with entries 2, 3, 4, 5, 6, 7.

Which equation produces the values in the table?

y = 4x

y = 4 + x

y = One-fourthx

y = 4 – x ok

hope this may help you

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What is the distance between (0,-1), (5,1)​
BlackZzzverrR [31]

Answer:

square root of 29 or approximately 5.38

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Can someone please help me with this question?
MakcuM [25]
D is the answer. Hope this helped.
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You need to find the value of x
crimeas [40]

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Step-by-step explanation:

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3 years ago
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A N S W E R Q U I C K P L E A S E
chubhunter [2.5K]

Answer:

1. A

2. D

3. D

Step-by-step explanation:

The standard form of a parabola is

y=\frac{1}{4p}(x-h)^2+k            ..... (1)

Where, (h,k) is vertex, (h,k+p) is focus and y=k-p is directrix.

1. The directrix of a parabola is y=−8 . The focus of the parabola is (−2,−6) .

k-p=-8                   ...(a)

(h,k+p)=(-2,-6)

k+p=-6            .... (b)

h=-2

On solving (a) and (b),  we get k=-7 and p=1.

Put h=-2, k=-7 and p=1 in equation (1).

y=\frac{1}{4(1)}(x-(-2))^2+(-7)

y=\frac{1}{4}(x+2)^2-7

Therefore option A is correct.

2 The directrix of a parabola is the line y=5 . The focus of the parabola is (2,1) .

k-p=5                   ...(c)

(h,k+p)=(2,1)

k+p=1            .... (d)

h=2

On solving (c) and (d),  we get k=3 and p=-2.

Put h=2, k=3 and p=-2 in equation (1).

y=\frac{1}{4(-2)}(x-(2))^2+(3)

y=-\frac{1}{8}(x-2)^2+3

Therefore option D is correct.

3. The focus of a parabola is (0,−2) . The directrix of the parabola is the line y=−3 .

k-p=-3                   ...(e)

(h,k+p)=(0,-2)

k+p=-2            .... (f)

h=0

On solving (e) and (f),  we get k=-2.5 and p=0.5.

Put h=0, k=-2.5 and p=0.5 in equation (1).

y=\frac{1}{4(0.5)}(x-(0))^2+(-2.5)

y=\frac{1}{2}(x)^2-2.5

y=\frac{1}{2}(x)^2-\frac{5}{2}

Therefore option D is correct.

5 0
3 years ago
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