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Archy [21]
3 years ago
11

Bubba Bulldog and all of his dog friends love to hide bones! Bubba hid 4 bones, Barry hid 5 bones, Larry hid 10 bones, and Goby

hid 13 bones.
Find the mean number of dog bones.
_______dog bones
Mathematics
1 answer:
JulsSmile [24]3 years ago
6 0

Answer:8

Step-by-step explanation:

You find the average which is adding them all together then dividing by how many numbers you added.

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Can someone please explain to me how to get the answer for the question is the picture? I don't get it at all, and the internet
AlekseyPX

Answer:

The original price of the item is $28.

Step-by-step explanation:

So to find the original price, we have to divide the sale price by the result of one minus the discount in percentage form.

So:

First convert 25% to a decimal, 0.25.

OP(original price) = 21 ÷ 1 - 0.25 =

1 - 0.25 = 0.75

21 ÷ 0.75 = 28.

5 0
3 years ago
There are three boxes: one with two golden coins, one with two silver coins, and one with one golden coin and one silver coin. A
krek1111 [17]

Answer:

Step-by-step explanation:

From Bayes' theorem is stated mathematically as the following equation:[2]

{\displaystyle P(A\mid B)={\frac {P(B\mid A)\,P(A)}{P(B)}},}

where A and B are events and P(B) ≠ 0.

P(A) and P(B) are the probabilities of observing A and B without regard to each other.

P(A | B), a conditional probability, is the probability of observing event A given that B is true.

P(B | A) is the probability of observing event B given that A is true.

At this point, go through the attached file before you continue with part B.

Part B)

P(silver) = P(silver from SS)+P(silver from GS)

note P(SS)=P(GG)=P(GS) = 1/3

P(silver from SS) = 1

P(silver from GS) = 1/2

hence

P(Silver from SS) = 1/3

P(Silver from GS) = 1/3 *1/2

P(Silver) = 1/3*1+1/3*1/2

required probability = P(Silver from SS)/P(Silver) = 2/3

4 0
3 years ago
Name the theorem or postulate that lets you immediately conclude ∆ABD ≈ ∆CBD.
enot [183]
I think that the correct answer is D. SAS
But I’m no sure tho
Hope you get it right
7 0
2 years ago
Read 2 more answers
A college writing seminar increased its size by 50\PP, percent from the first to the second day. If the total number of students
Jobisdone [24]

Answer: There were 10 students in the class on the first day.

Step-by-step explanation:

Let x be the number of students of the first day.

Given: A college writing seminar increased its size by 50 percent from the first to the second day.

i.e. Number of students on second day = (Number of students on first day)+(50% of Number of students on first day)

= x +50% of x

= x+0.50x

= (1.50)x

=1.50x

Since, it is given that  the total number of students in the seminar on the second day was 15.

i.e. 1.50x=15

\Rightarrow\ x=\dfrac{15}{1.5}\Rightarrow\ x=\dfrac{150}{15}\\\\\Rightarrow\ x=10

Hence, there were 10 students in the class on the first day.

7 0
3 years ago
if a class of 20 students 40% are boys. twenty-five percent often boys and 50% of the girls wear glasses. how many students wear
shtirl [24]
2 boys and 6 girls wear glasses, so 8 students wear glasses
7 0
3 years ago
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