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Alja [10]
4 years ago
12

Simplify the rational expression. state any excluded values. x2-x-6/x 2

Mathematics
1 answer:
Vinvika [58]4 years ago
7 0

So excluded values are x=3 and x=-2. Fully simplified form:

<span><span>1 over</span></span>

<span><span>x+2</span></span>

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Solve the equation x – 5 = 0.1(x + 5) for x. Round your answer to the nearest hundredth.
Nadusha1986 [10]

Answer:

x=6.111....

Step-by-step explanation:

x-5=0.1(x+5)

distribute 0.1 into (x+5)

x-5=0.1x+0.5

subtract 0.1x on both sides

x-0.1x-5=0.5

combine like terms

0.9x-5=0.5

add -5 on both sides

0.9x=5.5

divide both sides by 0.9

\frac{0.9x}{0.9} =\frac{5.5}{0.9}

x=55/9 or 6.11111.......

hope this helps

7 0
4 years ago
If an exponential model was used to fit the data set below, which of the following would be the best prediction for the output o
satela [25.4K]

Answer:

The equation is found to be: y = 50.6e^{0.16x}

y(20) = 1241.34

Step-by-step explanation:

The given data is:

x:   3          7         11        14          17

y: 83      142      301     450      722

Now, we find sum summation values, relevant to the formula of exponential regression model, using calculator:

∑ ln y = 27.77305, ∑x ln y = 308.1494, ∑x = 52, ∑ x² = 664

and, n = no. of data points = 5

Now, we use formulae of exponential regression model to find out values of constant:

b = (n∑x lny - ∑x ∑ln y)/[n∑x² - (∑x)²]

b = [(5)(308.1494) - (52)(27.77305)]/[(5)(664) - (52)²]

b = 0.16

Now, for a;

a = (∑ln y - b∑x)/n

Therefore,

a = [(27.77305) - (0.16)(52)]/5

a = 3.9

For, α:

α = e^a = e^3.9

α = 50.6

So, the final equation of exponential regression model is given as:

y = \alpha e^{bx}\\ y = 50.6e^{0.16x}

Now, we find value of y for x = 20:

y(20) = (50.6) e^(0.16*20)

<u>y(20) = 1241.34</u>

8 0
3 years ago
Recall the scenario about Eric's weekly wages in the lesson practice section. Eric's boss have been very impressed with his work
Alona [7]

Answer:  

1)\quad f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) D: x = [0, 24]

3) R: y = [0, 384]

4) see graph

<u>Step-by-step explanation:</u>

Eric's regular wage is $12 per hour for all hours less than 9 hours.

The minimum number of hours Eric can work each day is 0.

f(x) = 12x    for   0 ≤ x < 9

Eric's overtime wage is $18 per hour for 9 hours and greater.

The maximum number of hours Eric can work each day is 24 (because there are only 24 hours in a day).

f(x) = 18(x - 8) + 12(8)

    = 18x - 144 + 96

    = 18x - 48           for 9 ≤ x ≤ 24

The daily wage where x represents the number of hours worked can be displayed in function format as follows:

f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) Domain represents the x-values (number of hours Eric can work).

The minimum hours he can work in one day is 0 and the maximum he can work in one day is 24.

D:  0 ≤ x ≤ 24        →        D: x = [0, 24]

3) Range represents the y-values (wage Eric will earn).

Eric's wage depends on the number of hours he works. Use the Domain (given above) to find the wage.

The minimum hours he can work in one day is 0.

f(x) = 12x

f(0) = 12(0)

     =  0

The maximum hours he can work in one day is 24 <em>(although unlikely, it is theoretically possible).</em>

f(x) = 18x - 48

f(24) = 18(24) - 48

       = 432 - 48

       = 384

D:  0 ≤ y ≤ 384        →        D: x = [0, 384]

4) see graph.

Notice that there is an open dot at x = 9 for f(x) = 12x

and a closed dot at x = 9 for f(x) = 18x - 48

4 0
3 years ago
2. A store is to pack pencils in boxes of 10 and 12 pieces. What is the smallest number of pencils that can be packed using the
Taya2010 [7]

Answer:

2

Step-by-step explanation:

Obtain the greatest common factor of both 12 and 10

Factors of 10 = 1, 2, 5, 10

Factors of 12 = 1, 2, 3, 4, 6, 12

From the above, the greatest common factor of 10 and 12 is 2

Hence, smallest number of pencils using the boxes is 2

3 0
3 years ago
Juan and his sister collected 108 shells while at the beach. Of the shells they collected, 79 were white. Write and solve an equ
Aleks [24]

Answer:

108-79=29

Step-by-step explanation:

5 0
3 years ago
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