Show a way to count from 668 to 900 using ones tens and hundreds
2 answers:
Answer:
Step-by-step explanation:
We have to count from 668 to 900. Basically we have to reach from 668 to 900.
This could be similar to jumping on a number line from 668 to 900.
We could use ones, tens and hundreds to do so.
If we take two jumps of 100 from 668, then,
, we reach 868.
If we take a jump of three tens from 868, then,
, we reach 898.
If we take a jump of two ones, then,
, hence, we reach 900.
Thus, we have to take two jumps of 100, three jumps of ten and two jumps of one to reach 900 from 668.
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Answer:
AKPOS/ACGF = 28√3 -48 ≈ 0.497423
Step-by-step explanation:
Let's assume the square is a unit square. Then the height of the triangle is ...
1 +(√3)/2 = h
and half the base of the triangle is ...
h/√3 = (√3)/3 +1/2 = b/2
The area of the triangle is the product of these:
A = (1/2)bh
= (2 +√3)/2 × (3 +2√3)/6
= (6 +3√3 +4√3 +6)/12 = (12 +7√3)/12
So, the ratio of the area of the square to that of the triangle is the inverse of this, or ...
(square area)/(triangle area) = 12/(12+7√3)
(square area)/(triangle area) = 28√3 -48
