Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.
Step-by-step explanation:
Since we have given that
Integers between 10000 and 99999 = 99999-10000+1=90000
n( divisible by 3) = 
n( divisible by 5) = 
n( divisible by 7) = 
n( divisible by 3 and 5) = n(3∩5)=
n( divisible by 5 and 7) = n(5∩7) = 
n( divisible by 3 and 7) = n(3∩7) = 
n( divisible by 3,5 and 7) = n(3∩5∩7) = 
As we know the formula,
n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)
Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.
Answer:
29.56
Step-by-step explanation:
From the given diagram
x = hypotenuse
27 = adjacent
Using SOH CAH TOA identity
cos theta = adj/hyp.
Cos 24 = 27/x
x = 27/cos24
x = 29.56
Hence the value of x to the hundredth place is 29.56
Answer:
The population of the students at the University after 5 years is <u>442</u>.
Step-by-step explanation:
Given:
Current population of students is, 
Growth rate is, 
Time after which population is needed is, 
Let 'P' be the population after 't' years.
Population growth is an exponential growth and the equation to determine the population after 't' years is given as:
Now, plug in 400 for 
, 0.02 for 'r', 5 for 't' and solve for 'P'. This gives,
Therefore, the population of the students at the University after 5 years is 442.
