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3 years ago

6

At 8:00 a.m. the temperature outside in Juneau, Alaska was -16.5 . By noon the temperature had increased by 15.25 . What is the

temperature at noon?

1 answer:

adelina 88 [10]3 years ago

3 0

It would be -1.25 degrees at noon.

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Bill paints murals. He recorded the total amount of white paint that he used for his murals each month in the table below.

kicyunya [14]

Answer:

Step-by-step explanation:

2/3x4/5=8/15

6 0

3 years ago

Read 2 more answers

I’m the triangle shown below what is the approximate value of x

Dafna1 [17]

Answer:

The answer is choice B: 22.52 units.

Step-by-step explanation:

We use the Pythagoras's theorem which says for a right triangle with sides $x,y$ and hypotenuse $z$ :

$x^2+y^2=z^2.$

In our case

$z=26$

$y=13$

So we solve for $x:$

$x=\sqrt{z^2-y^2}=\sqrt{26^2-13^2} =\boxed{22.52\: units.}$

Which is choice B.

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3 years ago

Express the solution graphically of – }(2x + 1) < 3.

Anit [1.1K]

Answer:

The third one counting from the top.

Step-by-step explanation:

We have the inequality:

(-1/3)*(2x + 1) < 3

The first thing we need to do is isolate x on one side of the inequality.

First we can by -3 in both sides of the inequality, and remember, because we are multiplying by a negative number, the inequality sign changes its direction:

(-3)*(-1/3)*(2x + 1) > 3*(-3)

(2x + 1) > -9

Now we can subtract 1 in both sides:

2*x + 1 - 1 > -9 - 1

2*x > -10

Now we can divide by 2 in both sides:

2*x/2 > -10/2

x > -5

Then we should see a number line such that all the points at the right of -5 are colored.

The correct option is the third one, counting from the top.

7 0

3 years ago

Video Example EXAMPLE 1 Find the linearization of the function f(x) = x + 1 at a = 3 and use it to approximate the numbers 3.98

Blizzard [7]

Answer:

the linearization is y = 1/4x +5/4

the linearization will produce <em>overestimates</em>

the values computed from this linearization are ...

f(3.98) ≈ 2.245

f(4.05) ≈ 2.2625

Step-by-step explanation:

Apparently, you have ...

$f(x)=\sqrt{x+1}$

from which you have correctly determined that ...

$f'(x)=\dfrac{1}{2\sqrt{x+1}}$

so that f(3) = 2 and f'(3) = 1/4. Putting these values into the point-slope form of the equation of a line, we get the linearization ...

g(x) = (1/4)(x -3) +2

g(x) = (1/4)x +5/4

__

The values from this linearization will be overestimates, as the curve f(x) is concave downward everywhere. The tangent (linearization) is necessarily above the curve everywhere.

__

At the given values, we find ...

g(3.98) = 2.245

g(4.05) = 2.2625

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3 years ago

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