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BaLLatris [955]
3 years ago
12

The probability of choosing a tennis ball out of a bag containing 5 rubber balls, 3 tennis balls, 6 bouncy balls , and 1 squishy

ball.
Mathematics
2 answers:
Anastaziya [24]3 years ago
8 0

Answer: 20% = 0.2

Step-by-step explanation:

-Add all the ball for a total frequency (15 balls)

-Find the frequency of each ball

5/15= 0.33

3/15= 0.2

6/15= 0.4

1/15= 0.67

-multiply by 100 to get a percentage.

VLD [36.1K]3 years ago
3 0

Answer:

1/5 or 1;5, or .2, or 20%

Step-by-step explanation:

First, lets add 5, 3,6 and 1 together.

5+3+6+1=15

3 of these are tennis balls. This, as a ratio, would be 3/15. Simpified, tis would be 1/5.

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Brainliest question please help please help me solve all the two problems please
alexgriva [62]

Answer:

(-1,5)

Step-by-step explanation:

up the x corridor and down the y axis.

4 0
3 years ago
Please answer !!!!!!!
Akimi4 [234]

The measure of all the angles is given below:

angle 1= 30

angle 2=  150

angle 3= 30

angle 4= 150

angle 5= 30

angle 6= 150

angle 7= 30

angle 8= 73.5

<h3>What is angle?</h3>

An angle is formed when two straight lines or rays meet at a common endpoint. The common point of contact is called the vertex of an angle.

As,

angle 1= 30 (Vertically opposite angle)

angle 7= 30 (corresponding angle)

angle 4+30= 180 (linear pair)

 angle 4= 150

angle 4= angle 2= 150 (Vertically opposite angle)

angle 2= angle 6= 150  (corresponding angle)

angle 1= angle 5= 30  (corresponding angle)

angle (2x+3)= angle 4  (corresponding angle)

     2x+3= 150

      x= 73.5

Lean more about angle here:

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7 0
2 years ago
Which statement is true about the parts of this expression?
olganol [36]
<span>A) The constant is 7.5.  FALSE.  7.5 is a coefficient, not a constant.

</span><span>B) The coefficients are 7.5 and -9.  FALSE.  The coefficients are 7.5, -1/9 and 2.  50, being a constant, could be regarded as a coefficient in this case.

</span><span>C) The variables are x and y.  FALSE.  There are three variables:  x, y and z.

</span><span>D) The like terms are 7.5y and 2y.  TRUE.  The variable (y) is the same in each term.</span><span>

</span>
4 0
3 years ago
Read 2 more answers
Which is the equation of the function?
dlinn [17]

Answer

its the third one.

Step-by-step explanation:

7 0
3 years ago
For which system of equations is (5, 3) the solution? A. 3x – 2y = 9 3x + 2y = 14 B. x – y = –2 4x – 3y = 11 C. –2x – y = –13 x
Alla [95]
The <u>correct answer</u> is:

D) \left \{ {{2x-y=7} \atop {2x+7y=31}} \right..

Explanation:

We solve each system to find the correct answer.

<u>For A:</u>
\left \{ {{3x-2y=9} \atop {3x+2y=14}} \right.

Since we have the coefficients of both variables the same, we will use <u>elimination </u>to solve this.  

Since the coefficients of y are -2 and 2, we can add the equations to solve, since -2+2=0 and cancels the y variable:
\left \{ {{3x-2y=9} \atop {+(3x+2y=14)}} \right. &#10;\\&#10;\\6x=23

Next we divide both sides by 6:
6x/6 = 23/6
x = 23/6

This is <u>not the x-coordinate</u> of the answer we are looking for, so <u>A is not correct</u>.

<u>For B</u>:
\left \{ {{x-y=-2} \atop {4x-3y=11}} \right.

For this equation, it will be easier to isolate a variable and use <u>substitution</u>, since the coefficient of both x and y in the first equation is 1:
x-y=-2

Add y to both sides:
x-y+y=-2+y
x=-2+y

We now substitute this in place of x in the second equation:
4x-3y=11
4(-2+y)-3y=11

Using the distributive property, we have:
4(-2)+4(y)-3y=11
-8+4y-3y=11

Combining like terms, we have:
-8+y=11

Add 8 to each side:
-8+y+8=11+8
y=19

This is <u>not the y-coordinate</u> of the answer we're looking for, so <u>B is not correct</u>.

<u>For C</u>:
Since the coefficient of x in the second equation is 1, we will use <u>substitution</u> again.

x+2y=-11

To isolate x, subtract 2y from each side:
x+2y-2y=-11-2y
x=-11-2y

Now substitute this in place of x in the first equation:
-2x-y=-13
-2(-11-2y)-y=-13

Using the distributive property, we have:
-2(-11)-2(-2y)-y=-13
22+4y-y=-13

Combining like terms:
22+3y=-13

Subtract 22 from each side:
22+3y-22=-13-22
3y=-35

Divide both sides by 3:
3y/3 = -35/3
y = -35/3

This is <u>not the y-coordinate</u> of the answer we're looking for, so <u>C is not correct</u>.  

<u>For D</u>:
Since the coefficients of x are the same in each equation, we will use <u>elimination</u>.  We have 2x in each equation; to eliminate this, we will subtract, since 2x-2x=0:

\left \{ {{2x-y=7} \atop {-(2x+7y=31)}} \right. &#10;\\&#10;\\-8y=-24

Divide both sides by -8:
-8y/-8 = -24/-8
y=3

The y-coordinate is correct; next we check the x-coordinate  Substitute the value for y into the first equation:
2x-y=7
2x-3=7

Add 3 to each side:
2x-3+3=7+3
2x=10

Divide each side by 2:
2x/2=10/2
x=5

This gives us the x- and y-coordinate we need, so <u>D is the correct answer</u>.
7 0
3 years ago
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