Answer: he invested $120000 at 6% and $281000 at 9%
Step-by-step explanation:
Let x represent the amount invested at 6%
Let y represent the amount invested at 9%
The Actor invest some money at 6% and $41000 more than twice the amount at 9%. This means that
y = 2x + 41000- - - - - - - - - 1
The interest gotten from x is
6/100 × x = 0.06x
The interest gotten from y is
9/100 × y = 0.09y
The total annual interest earned from the investment is $32490. It means that
0.06x + 0.09y = 32490- - - - - - - - -2
Substituting equation 1 into equation 2, it becomes
0.06x + 0.09(2x + 41000) = 32490
0.06x + 0.18x + 3690 = 32490
0.06x + 0.18x = 32490 - 3690
0.24x = 28800
x = 28800/0.24
x = 120000
Substituting x = 120000 into equation 1, it becomes
y = 2(120000) + 41000
y = 281000
