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solniwko [45]
3 years ago
14

(_+_-_+_) - (_+_-_+_) = 0

Mathematics
1 answer:
Naily [24]3 years ago
7 0

Answer:

??????

Step-by-step explanation:

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Which equation is equivalent to the given equation?<br> x² - 6x = 8
Orlov [11]
Answer x^2-6x-8=0


I hope this helps

3 0
2 years ago
Please solve, -8-2(7r+1)=-94​
skelet666 [1.2K]

Answer:

r = 6

Step-by-step explanation:

Hello!

-8 - 2(7r + 1) = -94

Add 8 to both sides

-2(7r + 1) = -86

Divide both sides by -2

7r + 1 = 43

Subtract 1 from both sides

7r = 42

Divide both sides by 7

r = 6

Hope this Helps

4 0
3 years ago
Read 2 more answers
Okay, so lets say a teacher wants to divide her class of 30 students into 10 groups, but not necessarily of equal size. What are
Phantasy [73]
Well, she could do 30/10 which equals 3. So she could do 10 groups with 3 students in each group.
7 0
3 years ago
Read 2 more answers
PLEASE HELP QUICK!! WILL OFFER 100 POINTS TO THE FIRST ONE THAT ANSWERS
Reil [10]

Given

x+1 = \sqrt{7x+15}

We have to set the restraint

x+1\geq 0 \iff x \geq -1

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

(x+1)^2=7x+15 \iff x^2+2x+1=7x+15 \iff x^2-5x-14 = 0

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.

Similarly, we have

x-3 = \sqrt{x-1}+4 \iff x-7=\sqrt{x-1}

So, we have to impose

x-7\geq 0 \iff x \geq 7

Squaring both sides, we have

(x-7)^2=x-1 \iff x^2-14x+49=x-1 \iff x^2-15x+50 = 0

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.

7 0
3 years ago
The area of the base of this prism is 35cm^2 , what is the volume of the prism
mr Goodwill [35]
V=Bh what is the height of the prism? You do (35^2 )(height)
3 0
4 years ago
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