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Korolek [52]
3 years ago
6

What is the product of 7/16 and -6/13 I will make you the brainlest

Mathematics
1 answer:
mr_godi [17]3 years ago
5 0

Answer:

\frac{7}{16} *\frac{-6}{13} = \frac{-42}{208}

Step-by-step explanation:

\frac{7}{16} *\frac{-6}{13} = \frac{-42}{208} . First multiply 7*-6=-42.

Then do 16*13=208.

Simplify by dividing both by 2.

You get \frac{-42}{208}=\frac{-21}{104}.

Your final simplified answer is \frac{-21}{104}

I hope this helps!

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Joe has 1/2 of a pound of peanuts. He wants to share them equally among himself and 3 friends.
stealth61 [152]

Answer:

Each would get 0.125 pounds

Step-by-step explanation:

Divide 1/2 by 4 and you get 0.125

6 0
3 years ago
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Vika [28.1K]
Length of bc is 8
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3 0
2 years ago
Write the fraction as a whole or mixed number.
Wewaii [24]

Answer:

1\frac{1}{2}

Step-by-step explanation:

If there is 1500 cellular phones per 1000 people, then the number of phones per person is:

\frac{1500}{1000} = \frac{15}{10} = \frac{3}{2}

Now we know that \frac{3}{2} = 1 + \frac{1}{2} = 1\frac{1}{2}

5 0
3 years ago
Given that 8 bolts and 6 nuts weigh 138grams and 3 bolts and 5 nuts weigh 71 grams. Find the weight of;(a)one bolt and one nut (
Viktor [21]

Answer:

(a) Weight of a bolt = 12 grms and weight of a nut is 7 gms. Weight of one bolt and one nut = 12 + 7 = 19 gms

(b) 69 gms

(c) 209 gms

Step-by-step explanation:

This problem relates to solution of 2 unknowns using simultaneous equations.

Let B be the weight of a single bolt and N be the weight of a single nut

Since 8 bolts and 6 nuts weigh 138 grams we get one of the equations as

8B + 6N = 138    (1)

The second equation in the unknowns is

3B + 5N = 71  (2)

To solve, we eliminate one of the unknowns by making its coefficients the same and subtracting one from the other

Multiplying (1) by 5 ===>   40B + 30N = 690   (3)

Multiplying (2) by 6 ===>  18B + 30N = 426    (4)

(3) - (4) eliminates the N variables and yields

22B = 264   ==> B = 264/22 ==> B = 12

So the weight of a single bolt is 12 grams

We can find the weight of a single nut by substituting this value of B into any of the equations (1), (2), (3) or (4) and solving for N. Let's use equation (2)

3(12) + 5N = 71 ==>  36 + 5N = 71 ==> 5N = 71-36 = 35 ==>  N= 7

So the weight of a single nut is 7 grams

Weight of one bolt and one nut is the sum of the above individual weights = 12 + 7 = 19 gms

To solve (b) and (c) we could set up two other equations and plug in values for B and N

(b) 4B + 3N = 4.12 + 3.7 = 69
However, an alternate way is to perceive that 4B + 3N is exactly half of 8B + 6N so the value of that must be 138/2 = 69

(c) If we add both equations (1) and (2), we get

11B + 11N = 138 + 71 = 209 which is the equation for the total weight of 11 bolts and 11 nuts

5 0
1 year ago
Draw two different shapes with a perimeter of 16 units. What is the area of each shape?
Nadusha1986 [10]

<u>Shape #1:  A square.</u> 
Every side is  4  units long. 
The perimeter is  16  units.
The area is  <em>16  </em>square units.

<u>Shape #2:  A rectangle.</u>
The length is  7.9  units.
The width is  0.1  unit.
The perimeter is  16  units.
The area is  <em>0.79</em>  of a square unit.

<u>Shape #3:  A circle.</u>
The diameter is  (16/π)  units.  (about  5.093  units)
The perimeter (circumference) is 16 units.
The area is  (64/π)  square units.          (about  <em>20.37</em>  square units)


8 0
3 years ago
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