A uniform distribution is defined over the interval from 6 to 10.

Mathematics

1 answer:

scoundrel [369]3 years ago

6 0

Are you given an equation?

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A customer buys 15.5 cheese pizzas which are $10.50 each. What is the total? Round it to the nearest hundredth.

Cerrena [4.2K]

First of all, how do you buy exactly 15.5 pizzas?
what is a 0.5 pizza?

anyway

cost=cost per pizza times number of pizzas
cost per pizza=10.50
number of pizzas=15.5

cost=10.50 times 15.5
cost=162.75

total cost is $162.75

5 0

4 years ago

Which expression is equal to 9(6 - t)? How do you know?

Gnesinka [82]

Answer:

54-9t

Step-by-step explanation:

multiply the 9 with 6 and multiply 9 with the t which has an invisible 1

4 0

3 years ago

Read 2 more answers

Questions attached as screenshot below:Please help me I need good explanations before final testI pay attention

Nikitich [7]

The acceleration of the particle is given by the formula mentioned below:

$a=\frac{d^2s}{dt^2}$

Differentiate the position vector with respect to t.

$\begin{gathered} \frac{ds(t)}{dt}=\frac{d}{dt}\sqrt[]{\mleft(t^3+1\mright)} \\ =-\frac{1}{2}(t^3+1)^{-\frac{1}{2}}\times3t^2 \\ =\frac{3}{2}\frac{t^2}{\sqrt{(t^3+1)}} \end{gathered}$

Differentiate both sides of the obtained equation with respect to t.

$\begin{gathered} \frac{d^2s(t)}{dx^2}=\frac{3}{2}(\frac{2t}{\sqrt[]{(t^3+1)}}+t^2(-\frac{3}{2})\times\frac{1}{(t^3+1)^{\frac{3}{2}}}) \\ =\frac{3t}{\sqrt[]{(t^3+1)}}-\frac{9}{4}\frac{t^2}{(t^3+1)^{\frac{3}{2}}} \end{gathered}$

Substitute t=2 in the above equation to obtain the acceleration of the particle at 2 seconds.