Answer:
<h2>The vessel in distress is located in between vessels A and B</h2>
Step-by-step explanation:
To describe how we arrive at the answer, we are going to use the drawing i have attached to this response.
southwest of ship A is just a distance around the third quadrant (using the cardinal point) and it is below A
North of B is few distances ahead of ship B.
<em>Please see the attached sketch </em>
<h3>#a</h3>
∠XBC= 55°
[ By corresponding angles]
- Corresponding angle are the angles which hold sane relative position as another angle but somewhere else on the figure.
<h3>#b</h3>
∵ XB and XC are equal, ∠XBC=∠BCX
<h3>Now, With angle sum property of triangle: </h3>
Answer:
3/32 , 5/16 , 3/8 , 1/2 , 3/4
Step-by-step explanation:
Multiply them to give them all a common denominator of 32
Nick has fewer trading cards. 189 < 198; there is a difference of 9.
The enclosed shape is that of a trapezoid. The area of a trapezoid is the product of the height of it (measured perpendicular to the parallel bases) and the average length of the two parallel bases. The formula is generally written ...
... A = (1/2)(b₁ + b₂)·h
Here, the base lengths are the y-coordinates at x=4 and x=9. The height is the distance between those two x-coordinates: 9 - 4 = 5.
You are expected to find the y-values at those two points, then use the formula for the area of the trapezoid.
You can save a little work if you realize that the average of the two base lengths is the y-coordinate corresponding to the average x-coordinate: (9+4)/2 = 6.5. That is you only need to find the y-coordinate for x=6.5 and do the area math as though you had a rectangle of that height and width 5.
Going that route, we have
... y = 2(6.5) - 1 = 13 - 1 = 12
Then the trapezoid's area is
... A = 12·5 = 60 . . . . square units.
