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3 years ago

A 3-pack of beaded necklaces costs $4.47. What is the unit price?

Mathematics

2 answers:

inysia [295]3 years ago

7 0

Answer:

1.49 per necklace

Step-by-step explanation:

there are 3 necklaces sold for 4.47. if we divide the three necklaces by the overall price we get the price per necklace. 4.47 divided by 3 = 1.49

stepladder [879]3 years ago

6 0

Answer:

Each necklace cost $1.49

Step-by-step explanation:

Three necklaces cost $4.47. So to see how much one necklace cost you must divide the cost of all three necklaces by 3. Then you get $1.49

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Write the equation of each line using the given information.

MrRissso [65]

Answer:

See explanation.

Step-by-step explanation:

We need a point and a slope to have a point slope equation.

$y-y_{1}=m(x-x_{1})$

We need a slope and y-intercept to write in slope intercept form.

$y=mx+b$

A) $y-1=\frac{1}{2}(x+4)$ or $y=\frac{1}{2}x+3$

B) $y+1=-1(x-2)$

C) $y-1=0(x-1)$

D) $y=-3x+8$

4 0

3 years ago

Simplify 4x + 7 + 11x

ozzi

15x plus 7
This is because you just simplify the like terms

5 0

3 years ago

How how is 1/2 + 1/4 solve differently than 1/2 + 1/3?

yulyashka [42]

1/2 + 1/4 =
2/4 + 1/4 =
3/4 <===

7 0

3 years ago

Read 2 more answers

Solve the inequality 4p+7-p<31

AnnyKZ [126]

P<8
hope this helps you

3 0

3 years ago

What is the common denominator of (5/x^2-4) - (2/x+2) in the complex fraction (2/x-2) - (3/x^2-4)/(5/x^2-4) - (2/x+2)

PIT_PIT [208]

9514 1404 393

Answer:

common denominator: (x² -4)
simplified complex fraction: (2x +1)/(9 -2x)

Step-by-step explanation:

It is helpful to remember the factoring of the difference of squares:

a² -b² = (a -b)(a +b)

Your denominator of (x² -4) factors as (x -2)(x +2). You will note that one of these factors is the same as the denominator in the other fraction.

It looks like you want to simplify ...

$\dfrac{\left(\dfrac{2}{x-2}-\dfrac{3}{x^2-4}\right)}{\left(\dfrac{5}{x^2-4}-\dfrac{2}{x+2}\right)}=\dfrac{\left(\dfrac{2(x+2)}{(x-2)(x+2)}-\dfrac{3}{(x-2)(x+2)}\right)}{\left(\dfrac{5}{(x-2)(x+2)}-\dfrac{2(x-2)}{(x-2)(x+2)}\right)}\\\\=\dfrac{2(x+2)-3}{5-2(x-2)}=\boxed{\dfrac{2x+1}{9-2x}}$

3 0

3 years ago