Answer:
The mother (Rhoda) is 46 years old.
The daughter (Tenica) is 18 years old
Step-by-step explanation:
Let the age of the mother (Rhoda) be m
Let the age of the daughter (Tenica) be d.
The sum of Rhonda and her daughter Tenica’s age is 64. This can be written as:
m + d = 64 ... (1)
The difference in their ages is 28. This can be written as:
m – d = 28 ... (2)
From the above illustrations, the equation obtained are:
m + d = 64 ... (1)
m – d = 28 ... (2)
Solving by elimination method:
Add equation 1 and 2 together
. m + d = 64
+ m – d = 28
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
2m = 92
Divide both side by 2
m = 92/2
m = 46
Substitute the value of m into any of the equation to obtain the value of d. Here, we shall use equation 1
m + d = 64
m = 46
46 + d = 64
Collect like terms
d = 64 – 46
d = 18
Therefore, the mother (Rhoda) is 46 years old and the daughter (Tenica) is 18 years old.
The greatest common factor of 10 and 20 is 10.
Answer: Time at which the meet = 10:17:24 am
Step-by-step explanation: Speed of Ivan = 12 mph
Speed of Kate = 16 mph
Total distance traveled = Initial separation = 40 miles
Ivan leaves his house at 8:00 a.m and Kate leaves her house at 9:30 a.m
If t is the time of catch up after Ivan starting, time taken by Kate is t - 1.5,
We have
Distance = Speed x Time
Total distance traveled = Distance traveled by Kate + Distance traveled by Ivan
40 = t x 12 + (t-1.5) x 16
40 = 28t - 24
28t = 64
t = 2.29 hours
So after 2.29 hours of Ivan's starting they meet,
Time = 8:00 am + 2.29 hours = 10:00 am + 0.29 x 60 minutes = 10:17am + 0.4 x 60 seconds = 10:17:24 am
Time at which the meet = 10:17:24 am
Answer:
Description
Step-by-step explanation:
5 = 47, vertical angles
6 = 74, triangle interior angles add up to 180
7 = 59, linear pairs add up to 180
